C. Energy and Momentum · Momentum and CollisionsWhat Conservation Laws Tell Us: Newton's Cradle, Reactionless Drives and the Neutrino
C3.4 C3.5 A2.2About 70 minutes
Learning goals- I can explain why conservation laws rule out perpetual motion machines and reactionless drives.
- I can use both conservation laws together to predict the outcome in Newton's cradle.
- I can explain how the energy and momentum of beta decay led Pauli to predict the neutrino.
- I can describe the contribution of the Sudbury Neutrino Observatory and Arthur B. McDonald.
Words to know
perpetual motion machine
An imagined machine that would run forever or produce more energy than it receives; it is impossible.
damping
The removal of energy from an oscillation, usually by converting it into thermal energy.
beta decay
A radioactive decay in which a nucleus emits an electron (beta-minus) or a positron, along with a neutrino or antineutrino.
neutrino
A neutral, extremely light particle that interacts very weakly with matter; predicted by Pauli in 1930 and detected in 1956.
energy spectrum
A graph of how many particles are emitted with each kinetic energy.
What the conservation laws forbid
Conservation laws do not just help you solve problems. They also tell you what cannot happen, and when nature seems to break them, they point to something new. This lesson looks at what the conservation laws rule out for mechanical systems (perpetual motion, reactionless drives) and how they pick the outcome for Newton's cradle, then tells one of the great detective stories of physics: how these two laws predicted a new particle, the neutrino, more than 25 years before anyone detected it. Part of that story was finished in a nickel mine near Sudbury, Ontario.
Two laws, two kinds of "impossible"
Remember from Work, Energy and Simple Harmonic Motion (the lesson Damped Harmonic Motion, Shock Absorbers and Perpetual Motion): conservation of energy rules out a perpetual motion machine, because no machine can put out more energy than it takes in, and real machines always lose some energy as thermal energy. Shock absorbers use that same loss on purpose: they turn the energy of a car's bouncing into thermal energy in oil.
Conservation of momentum rules out a different dream: a "reactionless drive", a sealed box that could push itself through space just by moving things around inside it. Every force inside the box comes with an equal and opposite third-law partner, also inside the box, so internal forces can never change the box's total momentum. A weight swung back and forth inside a sealed spacecraft can make the craft wobble, but its centre of mass cannot start moving. To move, a spacecraft must throw something out (see Rockets and Propulsion: Momentum in Action) or be pushed by something outside it.
Often the two laws work together: each one alone allows many outcomes, but only a few outcomes obey both. Newton's cradle is the classic example.
Worked exampleExample 1: Newton's cradle
In a Newton's cradle, five identical steel balls hang in a row. Two balls are pulled back and released, hitting the row at speed v. Show that "one ball flies off at 2v" obeys momentum but breaks energy conservation, while "two balls fly off at v" obeys both.
- Momentum in: 2mv. Kinetic energy in: 2 × ½mv² = mv².
- One ball out at 2v: momentum m(2v) = 2mv ✓. Kinetic energy ½m(2v)² = 2mv² ✗ (twice the input: energy would be created).
- Two balls out at v: momentum 2mv ✓. Kinetic energy 2 × ½mv² = mv² ✓.
Only two balls out at v obeys both laws (for nearly elastic collisions between steel balls). The two conservation laws together pick out what actually happens.
A crisis in beta decay
Remember from Grade 11: in the SPH3U unit Thermal and Nuclear Energy you met alpha and beta decay. In beta-minus decay, a neutron in a nucleus changes into a proton, and an electron (the beta particle) shoots out.
Think about what conservation laws predict for a nucleus at rest that splits into two pieces (like an explosion from rest, earlier in this unit):
- The two pieces must fly apart in exactly opposite directions with momenta of equal size.
- The energy released is shared in a fixed way: the lighter piece gets the fraction m_heavy ÷ (m₁ + m₂) of it.
- So every decay of the same kind should give the emitted particle the same kinetic energy.
That is exactly what happens in alpha decay: alpha particles from a given isotope come out with one sharp energy (or a few). But in 1914, James Chadwick showed that beta-decay electrons come out with a continuous range of energies, from almost zero up to a maximum. Most electrons were missing some energy. Later experiments also showed that the electron and the recoiling nucleus were not always moving in opposite directions: momentum seemed to be missing too.
Some leading physicists, including Niels Bohr, seriously considered that energy might not be conserved in individual nuclear events.
Left: in alpha decay (two products), every alpha particle from the same decay gets the same energy. Right: in beta decay, electrons have a continuous spread of energies up to a maximum. The difference was the first clue that a third, invisible particle shares the energy. (Sketch, not to scale.)Pauli's "desperate remedy"
In December 1930, Wolfgang Pauli wrote a famous letter to a physics meeting, addressed "Dear Radioactive Ladies and Gentlemen". Rather than give up conservation of energy, he proposed what he called a desperate remedy: beta decay produces a third particle, which:
- has no electric charge (charge is also conserved, and the proton and electron already balance it),
- has very little mass (because the most energetic electrons carry almost all the available energy),
- interacts so weakly with matter that it escapes every detector, carrying away the missing energy and momentum.
In 1933 to 1934, Enrico Fermi built a theory of beta decay that included Pauli's particle and named it the neutrino, Italian for "little neutral one". With three bodies sharing the energy, the electron can get any amount from almost zero to the maximum, exactly as observed. (Today we write the beta-minus product as an antineutrino, its antiparticle.)
Here the conservation laws were used as predictive tools: the properties of the neutrino (charge, approximate mass, the energy and momentum it carries) were worked out from what had to be conserved, years before it was found. In 1956, Clyde Cowan and Frederick Reines finally detected neutrinos produced in huge numbers by a nuclear reactor.
Momentum in one beta decay. The electron and recoiling nucleus do not move in opposite directions, so their momenta do not add to zero. The missing momentum (dashed) is what brings the total back to zero: it is carried by the neutrino.Worked exampleExample 2: A two-body decay has fixed energies
A uranium-238 nucleus at rest emits an alpha particle (mass number 4) at 1.4 × 10⁷ m/s, leaving a thorium-234 nucleus. Find the recoil speed of the thorium nucleus, and the fraction of the kinetic energy carried by the alpha particle. (Use mass numbers as the ratio of masses.)
- Momentum: m_α v_α = m_Th v_Th, so v_Th = (4 ÷ 234)(1.4 × 10⁷) ≈ 2.4 × 10⁵ m/s, in the opposite direction.
- For two pieces from rest, Ek(α) ÷ Ek(Th) = m_Th ÷ m_α = 234 ÷ 4.
- Fraction carried by the alpha: 234 ÷ (234 + 4) ≈ 0.983.
The thorium nucleus recoils at about 2.4 × 10⁵ m/s, and the alpha carries about 98% of the kinetic energy, the same in every such decay. That is why alpha energies are sharp.
Worked exampleExample 3: Finding the missing momentum
A nucleus at rest undergoes beta decay. The electron moves off with momentum 3.0 × 10⁻²² kg·m/s [E] and the recoiling nucleus with 4.0 × 10⁻²² kg·m/s [N]. Find the momentum of the neutrino.
- Total momentum must stay zero: p_e + p_N + p_ν = 0.
- p_e + p_N = (3.0, 4.0) × 10⁻²² kg·m/s, so p_ν = (−3.0, −4.0) × 10⁻²² kg·m/s.
- Size: √(3.0² + 4.0²) × 10⁻²² = 5.0 × 10⁻²² kg·m/s. Direction: tan⁻¹(4.0 ÷ 3.0) ≈ 53.1° south of west.
5.0 × 10⁻²² kg·m/s [W 53.1° S], carried by the (anti)neutrino.
Worked exampleExample 4: Finding the missing energy
A particular beta decay always releases 1.25 × 10⁻¹³ J of kinetic energy in total. In one decay, the electron is measured to have 0.50 × 10⁻¹³ J. The recoiling nucleus has a negligible share. How much energy does the neutrino carry?
- Energy is conserved: E_total = E_electron + E_neutrino (+ the nucleus's tiny share).
- E_neutrino = 1.25 × 10⁻¹³ − 0.50 × 10⁻¹³ = 0.75 × 10⁻¹³ J.
The neutrino carries 7.5 × 10⁻¹⁴ J in this decay. In another decay of the same kind, the split could be completely different; only the total is fixed.
A Canadian chapter: the Sudbury Neutrino Observatory
Neutrinos are so hard to stop that most pass straight through the whole Earth. To catch a few, physicists build huge detectors deep underground, where rock blocks other particles. The Sudbury Neutrino Observatory (SNO) was built about 2 km underground in the Creighton nickel mine near Sudbury, Ontario. Its heart was a large acrylic sphere holding 1000 tonnes of heavy water, on loan from Canada's nuclear program, watched by thousands of light sensors.
In 2001 and 2002, SNO showed that neutrinos from the Sun change type on the way to Earth, which is only possible if neutrinos have mass. This solved a decades-old puzzle about "missing" solar neutrinos. For this work, Arthur B. McDonald of Queen's University in Kingston shared the 2015 Nobel Prize in Physics with Takaaki Kajita of Japan. The lab has since grown into SNOLAB, which continues to study neutrinos and search for dark matter.
Particle physics, astrophysics and the engineering of detectors like SNO are careers that start with exactly the physics in this course.
Just for funRoughly 60 billion neutrinos from the Sun pass through every square centimetre of you every second, day and night (at night they come up through the Earth). Almost none of them notice you, and you will never notice them.
Hands-on activityA ruler-groove Newton's cradle
You need: 5 identical marbles (or steel ball bearings), 1 larger or heavier marble if you have one, and a ruler with a groove down the middle (or two rulers taped side by side with a narrow gap) on a flat table. Grown-up note: marbles are a choking hazard for young children; keep them away from little ones.
- Place 4 marbles touching in a row in the groove. Roll a fifth marble gently along the groove into the end of the row. How many marbles leave the far end?
- Roll two touching marbles into a row of three. Then three into a row of two.
- Predict, then test: what happens if a heavier marble hits the row of identical marbles?
- For each test, write what conservation of momentum alone allows, and what conservation of momentum and kinetic energy together require (use Example 1 as a model).
What to look for: one in gives one out, two in gives two out, and so on. The collisions are not perfectly elastic, so the marbles that leave move a little slower than the ones that came in, and the row may creep forward slightly. A heavier marble pushes out more than one light marble, or keeps rolling forward after the hit.
Your turn
1In a Newton's cradle, three balls are pulled back and released together at speed v. Predict the result and justify it with both conservation laws.
Three balls swing out at speed v. Momentum in = 3mv = momentum out; kinetic energy in = 3(½mv²) = kinetic energy out. Other combinations (for example, one ball at 3v) would conserve momentum but not kinetic energy.
2A radium-226 nucleus at rest emits an alpha particle (mass number 4) at 1.5 × 10⁷ m/s, leaving radon-222. Find the radon nucleus's recoil speed.
v = (4 ÷ 222)(1.5 × 10⁷) ≈ 2.7 × 10⁵ m/s, opposite to the alpha.
3In a beta decay of a nucleus at rest, the electron moves with momentum 6.0 × 10⁻²² kg·m/s [E] and the nucleus with 2.0 × 10⁻²² kg·m/s [W]. Find the neutrino's momentum.
Total must be zero: 6.0 − 2.0 + p_ν = 0 (east positive), so p_ν = −4.0 × 10⁻²²: 4.0 × 10⁻²² kg·m/s [W].
4In a beta decay of a nucleus at rest, the electron has momentum 5.0 × 10⁻²² kg·m/s [N] and the nucleus 1.2 × 10⁻²¹ kg·m/s [E]. Find the neutrino's momentum.
p_e + p_N = (12, 5.0) × 10⁻²². p_ν = (−12, −5.0) × 10⁻²²: size 13 × 10⁻²² = 1.3 × 10⁻²¹ kg·m/s, direction tan⁻¹(5.0 ÷ 12) ≈ 22.6°: [W 22.6° S].
5A beta decay releases a total of 2.8 × 10⁻¹³ J of kinetic energy. The electron gets 1.1 × 10⁻¹³ J. Ignoring the nucleus's share, how much does the neutrino get?
2.8 × 10⁻¹³ − 1.1 × 10⁻¹³ = 1.7 × 10⁻¹³ J.
6Explain why a perpetual motion machine is impossible.
Conservation of energy: a machine cannot produce more energy than it receives, and every real machine loses some energy to thermal energy through friction or resistance, so without an energy input it must eventually stop.
7What does a shock absorber do with the energy of a car's bouncing?
It converts the oscillation's energy into thermal energy (by forcing oil through small holes), so the bouncing dies out quickly.
More practice: warm-up
1Who first proposed the neutrino, and in what year?
2What does the word neutrino mean?
"Little neutral one" (in Italian; the name came from Enrico Fermi).
3Name the Canadian laboratory that showed neutrinos change type.
The Sudbury Neutrino Observatory (SNO), near Sudbury, Ontario (now part of SNOLAB).
4When a nucleus at rest splits into exactly two particles, how are their directions related?
They move in exactly opposite directions.
5In which kind of decay do the emitted particles have a continuous range of energies?
More practice: on your own
1Explain how the continuous energy spectrum of beta decay suggested a third particle.
If only two particles were produced, momentum and energy conservation would give the electron one fixed energy in every decay (as in alpha decay). A continuous range means the energy is shared differently each time, which requires at least a third particle to take the rest.
2Explain why, in a Newton's cradle, one ball hitting the row never sends two balls out at half its speed.
Momentum: m v = 2m(v/2) ✓. Kinetic energy out: 2 × ½m(v/2)² = ¼mv², which is only half of the ½mv² that came in. Steel balls are nearly elastic, so they do not lose half their energy; the outcome that conserves both is one ball out at v.
3An inventor claims a sealed spacecraft can move forward forever by swinging a heavy weight back and forth inside it, and never releases anything. Evaluate the claim.
The forces between the weight and the craft are internal, so the total momentum of the sealed system cannot change. The craft can wobble back and forth as the weight moves, but its centre of mass cannot start moving. The claim is false.
4A car's spring (k = 2.0 × 10⁴ N/m) is compressed 0.10 m by a bump. How much energy does it store? Describe what happens to that energy with good shocks and with worn-out shocks.
E = ½kx² = ½(2.0 × 10⁴)(0.10)² = 100 J. Good shocks turn most of it into thermal energy within about one bounce. Worn shocks remove it slowly, so the car bounces several times, making it harder to steer and brake.
5A free neutron at rest decays into a proton, an electron and an antineutrino. The proton's momentum is 2.0 × 10⁻²² kg·m/s [S] and the electron's is 6.0 × 10⁻²² kg·m/s [N 30° E]. Find the antineutrino's momentum.
Electron: (6.0 sin 30°, 6.0 cos 30°) = (3.0, 5.20). Proton: (0, −2.0). Sum (3.0, 3.20). Antineutrino: (−3.0, −3.20) × 10⁻²²: size ≈ 4.4 × 10⁻²² kg·m/s, at tan⁻¹(3.0 ÷ 3.20) ≈ 43° west of south: [S 43° W].
Challenge
1Show that, when a nucleus at rest splits into two particles, each particle's kinetic energy is fixed by the masses and the total energy released Q. What fraction does the lighter particle get?
Momenta equal in size: Ek₁ ÷ Ek₂ = m₂ ÷ m₁ (from the explosions lesson). With Ek₁ + Ek₂ = Q, Ek₁ = Q m₂ ÷ (m₁ + m₂) and Ek₂ = Q m₁ ÷ (m₁ + m₂). Both are fixed, so every such decay gives the same energies. The lighter particle (m₁ smaller) gets the larger fraction, m₂ ÷ (m₁ + m₂).
2Prove algebraically that if two identical balls moving at v hit a row of identical balls elastically and n balls leave together at speed u, then n = 2 and u = v.
Momentum: 2mv = nmu, so u = 2v ÷ n. Energy: 2(½mv²) = n(½mu²), so 2v² = nu² = n(4v² ÷ n²) = 4v² ÷ n. So n = 2, and then u = v.
3Estimate how many solar neutrinos pass through your body each second, using a flux of 6.5 × 10¹⁰ per cm² per second and an area of about 0.5 m² facing the Sun.
0.5 m² = 5000 cm². 5000 × 6.5 × 10¹⁰ ≈ 3 × 10¹⁴ per second, hundreds of trillions every second.
Check your understandingQuiz
1. In beta decay, the electrons emitted by nuclei of the same isotope have:
2. Pauli proposed the neutrino in 1930 in order to:
3. A nucleus at rest splits into exactly two particles. Which is true?
4. A sealed spacecraft that releases nothing tries to move by swinging a heavy weight back and forth inside it. What happens to its centre of mass?
6. Two balls of a Newton's cradle hit the row at speed v, and two balls leave at speed v. This happens because:
7. What did the Sudbury Neutrino Observatory show?
For parents and teachersBig idea (C3.4, C3.5): conservation of energy and momentum say what cannot happen (perpetual motion, reactionless drives) and, used together, predict outcomes such as Newton's cradle. In beta decay, missing energy and momentum led Pauli (1930) to predict the neutrino, named by Fermi and detected in 1956. Canada's Sudbury Neutrino Observatory later showed neutrinos have mass.
How to help: Try the marble Newton's cradle together (keep marbles away from young children). Ask your teen to tell the neutrino story in their own words: what was missing, what Pauli proposed, and why that was a bold choice.
Common difficulties:
- Two-body vs three-body decays. Two products: fixed, opposite momenta and fixed energies. Three products: energies and directions can vary.
- Thinking the neutrino was discovered first. It was predicted from the conservation laws first, then detected decades later.
- Internal forces: moving parts inside a closed system cannot change its total momentum.
- Vector arithmetic in the beta-decay momentum problems: draw the triangle.