C. Energy and Momentum · Momentum and CollisionsLinear Momentum: Mass in Motion
C2.1 C2.5 A1.12About 65 minutes
Learning goals- I can define linear momentum as p = mv and state its units and direction.
- I can calculate the momentum of an object and the total momentum of a system in one dimension, using a sign convention.
- I can calculate a change in momentum, including for an object that reverses direction.
- I can explain the difference between momentum and kinetic energy and use Ek = p²/(2m).
Words to know
linear momentum (p)
The product of an object's mass and velocity, p = mv. A vector in the direction of the velocity, measured in kg·m/s.
system
The object or group of objects chosen for study. Everything else is the surroundings.
total momentum
The vector sum of the momenta of all objects in a system.
change in momentum (Δp)
Final momentum minus initial momentum, Δp = p_f − p_i (a vector subtraction).
sign convention
A choice of which direction is positive in a one-dimensional problem.
Which is harder to stop?
Picture two things sliding toward you on the ice at the local arena. One is a curling stone gliding at a slow walking pace. The other is a hockey puck flying off a slapshot. The puck is much faster. But most people would much rather stop the puck than the stone. Why?
Stopping something depends on both its mass and its velocity. Physicists combine them into one quantity called linear momentum. Newton called it the quantity of motion. It is the star of this whole unit: in every collision, explosion and rocket launch you will study, momentum is the quantity that is shared, traded and conserved.
Remember from Grade 11: in SPH3U you used Newton's laws (F_net = ma, action-reaction pairs) and kinetic energy, Ek = ½mv². In the sibling unit Work, Energy and Simple Harmonic Motion you extended work and energy to two dimensions and added elastic potential energy. Momentum is new: this unit builds it from the ground up and then uses it alongside energy.
Defining momentum
The linear momentum of an object is its mass times its velocity:
p = mv
- p is momentum, in kilogram metres per second (kg·m/s).
- m is mass in kilograms, and v is velocity in metres per second.
Because velocity is a vector, momentum is a vector too. It points in the same direction as the velocity. A 2.0 kg cart moving 3.0 m/s east has a momentum of 6.0 kg·m/s east. The same cart moving 3.0 m/s west has 6.0 kg·m/s west. Those two momenta are not equal, even though their sizes match.
In one dimension, we handle direction with signs. Choose one direction as positive (usually east, right or up). Then a velocity or momentum the other way is negative. Always state your sign convention at the start of a problem.
The word linear separates this from angular momentum (the momentum of spinning objects), which you will meet in university physics. In this unit, "momentum" always means linear momentum.
The curling stone is 20 times slower than the puck, but because it is about 120 times more massive, its momentum (thick arrow) is about 6 times larger. Arrows are drawn to the scales shown.Worked exampleExample 1: Momentum of a puck and a car
(a) Find the momentum of a 0.16 kg hockey puck moving at 40 m/s [E]. (b) Find the momentum of a 1400 kg car moving at 90 km/h [N].
- (a) p = mv = (0.16 kg)(40 m/s) = 6.4 kg·m/s. The direction is the direction of the velocity.
- (b) Convert to m/s first: 90 km/h ÷ 3.6 = 25 m/s.
- p = mv = (1400 kg)(25 m/s) = 35 000 kg·m/s = 3.5 × 10⁴ kg·m/s, directed [N].
(a) 6.4 kg·m/s [E]. (b) 3.5 × 10⁴ kg·m/s [N].
Momentum and kinetic energy: two different ideas
Momentum and kinetic energy both depend on mass and speed, so students often mix them up. They are very different:
- Momentum p = mv is a vector. It depends on speed to the first power. Two objects moving in opposite directions can have momenta that cancel.
- Kinetic energy Ek = ½mv² is a scalar. It depends on speed squared. It is never negative, so kinetic energies never cancel.
You can link the two. Since v = p/m,
Ek = ½m(p/m)² = p² ÷ (2m), or equivalently p = √(2mEk).
This tells you something useful: if two objects have the same momentum, the lighter one has more kinetic energy. You will use this fact in explosions, where the lighter fragment always gets more of the energy.
Worked exampleExample 2: The stone and the puck
Compare the momentum and the kinetic energy of a 19 kg curling stone moving at 2.0 m/s and a 0.16 kg puck moving at 40 m/s.
- Stone: p = (19)(2.0) = 38 kg·m/s. Ek = ½(19)(2.0)² = 38 J.
- Puck: p = (0.16)(40) = 6.4 kg·m/s. Ek = ½(0.16)(40)² = 128 J ≈ 1.3 × 10² J.
- The stone has about 38 ÷ 6.4 ≈ 6 times the momentum of the puck.
- The puck has about 128 ÷ 38 ≈ 3.4 times the kinetic energy of the stone.
The stone has more momentum (38 kg·m/s vs 6.4 kg·m/s), but the puck has more kinetic energy (about 130 J vs 38 J). Being harder to stop in a given time is about momentum; how much damage something can do over a distance is about energy.
Worked exampleExample 3: Kinetic energy from momentum
A 0.50 kg ball has a momentum of 3.0 kg·m/s. Find its kinetic energy without finding its speed first. Check your answer by finding the speed.
- Ek = p² ÷ (2m) = (3.0)² ÷ (2 × 0.50) = 9.0 ÷ 1.0 = 9.0 J.
- Check: v = p ÷ m = 3.0 ÷ 0.50 = 6.0 m/s, and Ek = ½(0.50)(6.0)² = 9.0 J. ✓
Momentum of a system, and change in momentum
A system is the group of objects you choose to study, such as two carts on a track or two players on the ice. The total momentum of a system is the vector sum of the momenta of all its parts:
p_total = m₁v₁ + m₂v₂ + ...
In one dimension, add with signs. In two dimensions (later in this unit), add vectors by components.
The change in momentum of an object is Δp = p_f − p_i (final minus initial). Because this is a vector subtraction, a ball that bounces back has a much bigger change in momentum than one that just stops: reversing direction means losing all your momentum and gaining momentum the other way.
A 0.15 kg ball hits a wall at 20 m/s east and bounces back at 15 m/s west, with east positive. To find Δp = p_f − p_i, add −p_i to p_f. The change (5.25 kg·m/s west) is bigger than either momentum alone. (Scale: 30 px per kg·m/s.)Worked exampleExample 4: Change in momentum in a bounce
A 0.15 kg ball moving at 20 m/s [E] hits a wall and bounces straight back at 15 m/s [W]. Find its change in momentum.
- Choose east as positive. Then v_i = +20 m/s and v_f = −15 m/s.
- p_i = (0.15)(+20) = +3.0 kg·m/s. p_f = (0.15)(−15) = −2.25 kg·m/s.
- Δp = p_f − p_i = −2.25 − (+3.0) = −5.25 kg·m/s.
- The negative sign means west.
Δp = 5.25 kg·m/s [W] (about 5.3 kg·m/s). A common mistake is to subtract the speeds and get 0.75 kg·m/s; that ignores the change of direction.
Worked exampleExample 5: Total momentum of two skaters
A 60 kg skater glides at 3.0 m/s [E]. An 80 kg skater glides at 2.0 m/s [W]. Find the total momentum of the two-skater system.
- Let east be positive.
- p₁ = (60)(+3.0) = +180 kg·m/s. p₂ = (80)(−2.0) = −160 kg·m/s.
- p_total = 180 + (−160) = +20 kg·m/s.
20 kg·m/s [E]. Notice that the total kinetic energy is ½(60)(3.0)² + ½(80)(2.0)² = 270 J + 160 J = 430 J. The energies add; the momenta partly cancel.
Units: kg·m/s and N·s
Momentum is measured in kg·m/s. Since 1 N = 1 kg·m/s², a newton-second is 1 N·s = 1 kg·m/s² × s = 1 kg·m/s. So N·s and kg·m/s are the same unit. You will see N·s used for impulse in the next lesson.
Just for funNewton wrote about momentum in Latin, calling it quantitas motus, "quantity of motion". So if a teacher ever says you have a lot of momentum, they are really saying you have a large quantity of motion. Take it as a compliment.
Hands-on activityWhich ball is harder to stop?
You need: two or three balls of different masses (for example a tennis ball, a soccer ball and a basketball), a kitchen scale, a tape measure, masking tape, a phone stopwatch, and an empty cardboard box (a cereal box is fine). Work in a hallway or on a smooth floor, away from anything breakable.
- Weigh each ball on the kitchen scale and record its mass in kilograms (for example 58 g = 0.058 kg).
- Tape a start line and a target line 2.0 m apart. Put the empty box on its side just past the target line.
- Roll a ball from the start line so it hits the box. Time how long it takes to travel the 2.0 m. Average speed v = 2.0 m ÷ time. Mark where the box ends up.
- Repeat with each ball, trying to roll them at about the same speed. Then try the light ball much faster.
- Calculate p = mv for every roll. Rank the rolls by momentum and by how far the box slid.
What to look for: at similar speeds, the heavier ball pushes the box farther. A light ball rolled fast can match a heavy ball rolled slowly when their momenta are similar. Your rolling speed slows a little across the floor, so your values of v are averages; that is fine for a comparison.
Your turn
1Find the momentum of a 0.43 kg soccer ball moving at 18 m/s [N].
p = (0.43)(18) = 7.7 kg·m/s [N] (7.74 before rounding).
2A 65 kg cyclist rides a 10 kg bicycle at 8.0 m/s [W]. Find the momentum of the cyclist and bicycle together.
Total mass 75 kg. p = (75)(8.0) = 600 kg·m/s [W] (6.0 × 10² kg·m/s).
3A raindrop of mass 5.0 × 10⁻⁵ kg falls at 9.0 m/s. Find its momentum.
p = (5.0 × 10⁻⁵)(9.0) = 4.5 × 10⁻⁴ kg·m/s [down].
4How fast must a 0.16 kg puck move to have the same momentum as a 19 kg curling stone moving at 0.50 m/s?
The stone's p = (19)(0.50) = 9.5 kg·m/s. v = 9.5 ÷ 0.16 ≈ 59 m/s (about 210 km/h).
5A 9000 kg truck travels at 54 km/h [S]. Find its momentum.
54 ÷ 3.6 = 15 m/s. p = (9000)(15) = 1.35 × 10⁵ kg·m/s [S] (about 1.4 × 10⁵).
6A 1.2 kg cart moves at 0.50 m/s [E] and a 0.80 kg cart moves at 1.5 m/s [W]. Find the total momentum.
East positive: (1.2)(0.50) + (0.80)(−1.5) = 0.60 − 1.20 = −0.60. 0.60 kg·m/s [W].
7A 1200 kg car has a momentum of 3.0 × 10⁴ kg·m/s. Find its kinetic energy using Ek = p²/(2m).
Ek = (3.0 × 10⁴)² ÷ (2 × 1200) = 9.0 × 10⁸ ÷ 2400 = 3.75 × 10⁵ J (about 3.8 × 10⁵ J).
More practice: warm-up
1What is the SI unit of momentum?
kg·m/s, which is the same as N·s.
2Find the momentum of a 2.0 kg object moving at 3.0 m/s [E].
p = (2.0)(3.0) = 6.0 kg·m/s [E].
3Is momentum a scalar or a vector?
A vector. It has the same direction as the velocity.
4If an object's speed doubles and its mass stays the same, what happens to its momentum?
It doubles, because p is proportional to v. (Its kinetic energy would become four times larger.)
5What is the momentum of a parked car?
Zero, because its velocity is zero.
More practice: on your own
1A 0.058 kg tennis ball has a momentum of 2.9 kg·m/s. How fast is it moving?
v = p ÷ m = 2.9 ÷ 0.058 = 50 m/s.
2A 1500 kg car moves at 20 m/s and a 12 000 kg truck moves at 2.5 m/s. Compare their momenta and their kinetic energies.
Both have p = 3.0 × 10⁴ kg·m/s. Ek(car) = ½(1500)(20)² = 3.0 × 10⁵ J; Ek(truck) = ½(12 000)(2.5)² = 3.75 × 10⁴ J. Same momentum, but the car has 8 times the kinetic energy, because Ek = p²/(2m) and the car's mass is 8 times smaller.
3A 0.50 kg ball moving at 4.0 m/s [E] is caught and stopped. Find its change in momentum.
East positive: Δp = 0 − (0.50)(4.0) = −2.0. Δp = 2.0 kg·m/s [W]: to stop it, momentum must be removed in the westward direction.
4A 70 kg runner speeds up so that her momentum goes from 280 kg·m/s [N] to 420 kg·m/s [N]. Find her initial and final speeds and her change in momentum.
v_i = 280 ÷ 70 = 4.0 m/s; v_f = 420 ÷ 70 = 6.0 m/s; Δp = 420 − 280 = 140 kg·m/s [N].
5A 1.0 kg object and a 4.0 kg object have the same kinetic energy. Which has more momentum, and by what factor?
p = √(2mEk). With equal Ek, p is proportional to √m. √(4.0 ÷ 1.0) = 2, so the 4.0 kg object has twice the momentum.
Challenge
1Show that the units kg·m/s and N·s are identical.
1 N = 1 kg·m/s² (from F = ma). So 1 N·s = (1 kg·m/s²)(1 s) = 1 kg·m/s. ✓
2A 0.20 kg ball is dropped from rest from a height of 1.8 m. Ignoring air resistance, find its momentum just before it hits the ground. (Use energy conservation from the sibling unit, or kinematics.)
mgh = ½mv² gives v = √(2gh) = √(2 × 9.8 × 1.8) = √35.28 ≈ 5.94 m/s. p = (0.20)(5.94) ≈ 1.2 kg·m/s [down].
3Three objects move along an east-west line: 2.0 kg at 3.0 m/s [E], 1.0 kg at 4.0 m/s [W], and a 3.0 kg object. The total momentum of the three is zero. Find the velocity of the 3.0 kg object.
East positive: (2.0)(3.0) + (1.0)(−4.0) + (3.0)v = 0, so 6.0 − 4.0 + 3.0v = 0 and v = −2.0 ÷ 3.0 ≈ −0.67 m/s. About 0.67 m/s [W].
Check your understandingQuiz
1. Which object has the greatest momentum?
2. Which unit is equivalent to kg·m/s?
3. The speed of an object triples. Its momentum:
4. Two identical carts move toward each other at the same speed. Which statement about the two-cart system is true?
5. An object has a momentum of 10 kg·m/s and a mass of 2.0 kg. What is its kinetic energy?
6. A ball of mass m moving at speed v bounces straight back off a wall with the same speed v. What is the magnitude of its change in momentum?
For parents and teachersBig idea (C2.1, C2.5): momentum p = mv is a vector that measures how much motion an object has. It is the foundation of the whole unit, because momentum is conserved in collisions and explosions.
How to help: Ask your teen to explain, in their own words, why a slow curling stone is harder to stop than a fast puck. Then ask the opposite question: which one has more kinetic energy? (The puck.) If they can explain both, they understand the difference between p = mv and Ek = ½mv².
Common difficulties:
- Forgetting direction. Momentum needs a direction or a sign. Encourage them to write "east is positive" (or similar) at the top of every problem.
- Bounces. For a ball that bounces back, Δp is found by subtracting vectors, so the sizes add (5.25 kg·m/s in Example 4, not 0.75).
- Unit conversions. Speeds in km/h must be divided by 3.6, and masses in grams divided by 1000.
- Mixing up momentum and kinetic energy. Momenta can cancel; kinetic energies cannot.