D. Gravitational, Electric, and Magnetic Fields · Gravitational, Electric and Magnetic FieldsKepler's Laws, Black Holes and Dark Matter
D2.2 D2.1About 70 minutes
Learning goals- I can state Kepler's three laws of planetary motion and explain them with Newton's law of gravitation.
- I can use T²/a³ = constant (and T² = 4π²a³/GM) to find periods, orbit sizes and the mass of a central body.
- I can explain how the orbits of stars show a supermassive black hole at the centre of our galaxy.
- I can explain how galaxy rotation curves give evidence for dark matter.
Words to know
ellipse
A closed oval curve. For every point on it, the sum of its distances to two fixed points (the foci) is the same.
focus (plural foci)
One of the two special points inside an ellipse. The Sun sits at one focus of each planet's orbit.
semi-major axis (a)
Half the longest diameter of an ellipse; the average of the closest and farthest distances from the focus. For a circle it is the radius.
perihelion / aphelion
The point in an orbit around the Sun closest to / farthest from the Sun.
Kepler's third law
For all bodies orbiting the same central mass, T²/a³ is the same constant, equal to 4π²/GM.
dark matter
Matter that does not emit or absorb light but has mass and makes gravitational fields. Its existence is inferred from its gravitational effects.
supermassive black hole
A black hole of millions to billions of solar masses at the centre of a galaxy. Ours, Sagittarius A∗, is about 4 million solar masses.
Closest to the Sun in January
Here is a fact that surprises most Canadians: Earth is closest to the Sun in early January, in the middle of our winter, and farthest in early July. Earth's orbit is not a perfect circle. (The seasons come from the tilt of Earth's axis, not from the changing distance.)
Remember from Grade 9 (SNC1W, Space Exploration): Johannes Kepler used Tycho Brahe's careful observations to show that planets move in ellipses. In this lesson you will see that Kepler's three laws all follow from Newton's law of universal gravitation, and then use them to "weigh" Jupiter, the black hole at the centre of our galaxy and the galaxy itself.
Kepler's three laws (1609 and 1619)
- Law of ellipses: each planet moves in an ellipse with the Sun at one focus.
- Law of equal areas: the line from the Sun to a planet sweeps out equal areas in equal times. So a planet moves fastest at perihelion (closest) and slowest at aphelion (farthest).
- Law of periods: for all planets orbiting the Sun, T²/a³ is the same, where T is the period and a is the semi-major axis.
Kepler found these laws from data, with no idea why they worked. About 70 years later, Newton showed that an inverse-square force of gravity produces exactly these three laws. The second law comes from the fact that gravity points straight at the Sun, so it cannot speed up or slow down the planet's sideways turning (this is conservation of angular momentum, a topic for first-year university physics).
Kepler's first and second laws. The Sun sits at one focus. The two shaded wedges are swept out in equal times and have equal areas, so the planet must move faster near perihelion.The third law from Newton
For a circular orbit (a = r), you already derived T² = (4π²/GM) r³. So:
T²/a³ = 4π²/GM
The right side contains only G and the central mass M. That is why every planet around the Sun has the same T²/a³, every moon of Jupiter has its own shared value, and every satellite of Earth has another. The law also works for elliptical orbits if you use the semi-major axis a.
Two handy ways to use it:
- Comparing two orbits around the same body: T₁²/a₁³ = T₂²/a₂³. For the Sun, with T in years and a in astronomical units (1 AU = 1.50 × 10¹¹ m, Earth's average distance), Earth gives T²/a³ = 1, so T² = a³ for every planet.
- Weighing the central body: M = 4π²a³/(GT²). Measure one orbit, get the mass.
Kepler's third law for the inner planets. When T² is plotted against a³, the points fall on one straight line through the origin, with slope 1 year²/AU³.Worked exampleExample 1: The period of Mars
Mars orbits the Sun with a semi-major axis of 1.52 AU. Find its period in Earth years.
- For the Sun, in years and AU: T² = a³.
- T² = (1.52)³ = 3.512.
- T = √3.512 = 1.87 years.
1.87 years (about 687 days). This is why missions to Mars launch only about every 26 months, when Earth and Mars line up well.
Worked exampleExample 2: Weighing Jupiter with its moon Io
Io orbits Jupiter with a = 4.22 × 10⁸ m and T = 1.769 days. Find Jupiter's mass.
- Convert T: 1.769 × 86 400 s = 1.528 × 10⁵ s.
- M = 4π²a³/(GT²) = 4π²(4.22 × 10⁸)³ / ((6.67 × 10⁻¹¹)(1.528 × 10⁵)²).
- Numerator: 4π² × 7.515 × 10²⁵ = 2.967 × 10²⁷. Denominator: 6.67 × 10⁻¹¹ × 2.336 × 10¹⁰ = 1.558.
- M = 2.967 × 10²⁷/1.558 = 1.90 × 10²⁷ kg.
1.90 × 10²⁷ kg, about 318 Earth masses. This is how the masses of planets with moons were first measured.
A black hole at the heart of the Milky Way
At the centre of our galaxy, astronomers have tracked individual stars for over 30 years using infrared telescopes (infrared light passes through the dust that blocks visible light). One star, called S2, follows an ellipse with a period of about 16 years and a semi-major axis of roughly 1000 AU. Its focus is an object that gives off almost no light: Sagittarius A\*.
Using Kepler's third law with solar units (masses in solar masses, a in AU, T in years, M = a³/T²):
M ≈ (1000)³/(16)² ≈ 3.9 × 10⁶ solar masses.
About 4 million Suns packed inside S2's closest approach (about 120 AU, about four times the Sun-Neptune distance). The only object that can hold so much mass in so small a space is a black hole. The 2020 Nobel Prize in Physics was shared by three people: Roger Penrose, for showing that black holes follow from general relativity, and Reinhard Genzel and Andrea Ghez, whose teams tracked these stars. In 2022 the Event Horizon Telescope collaboration released the first image of the shadow of Sagittarius A\*. You will meet black holes again in the next lesson.
Worked exampleExample 3: Galaxy mass from the Sun's orbit
The Sun orbits the centre of the Milky Way at about 230 km/s, at a distance of about 2.5 × 10²⁰ m (26 000 light-years). Estimate the mass of the galaxy inside the Sun's orbit.
- Treat the orbit as circular: v² = GM/r, so M = v²r/G.
- M = (2.30 × 10⁵)²(2.5 × 10²⁰)/(6.67 × 10⁻¹¹).
- M = (5.29 × 10¹⁰)(2.5 × 10²⁰)/(6.67 × 10⁻¹¹) = 2.0 × 10⁴¹ kg.
- In solar masses: 2.0 × 10⁴¹/1.99 × 10³⁰ ≈ 1 × 10¹¹.
About 2 × 10⁴¹ kg, or roughly 100 billion solar masses inside the Sun's orbit.
The case for dark matter
If most of a galaxy's mass were in its bright centre, stars far out would orbit slower, following v = √(GM/r) like the outer planets do. In the 1970s, Vera Rubin and Kent Ford measured how fast stars and gas orbit in spiral galaxies. Far from the centre, the speeds did not drop. The rotation curves stayed flat.
For v to stay constant as r grows, M = v²r/G must grow in proportion to r: there must be more and more mass farther out, where there is very little light. This unseen mass is called dark matter. Other evidence agrees: in the 1930s Fritz Zwicky found galaxies in clusters moving too fast to be held by their visible mass, and the bending of light by clusters (gravitational lensing) shows more mass than we can see. Current estimates suggest dark matter outweighs ordinary matter by about five to one.
Nobody yet knows what dark matter is. SNOLAB, an underground laboratory 2 km below the surface near Sudbury, Ontario, hosts experiments searching for dark-matter particles, shielded from cosmic rays by the rock above.
Galaxy rotation curves. If the visible matter were all the mass, orbital speeds would fall off beyond the bright centre (lower curve). Measured speeds stay roughly flat (upper curve), which points to dark matter.Just for funDark matter outweighs all the stars, planets, gas and dust in the universe roughly five to one, and nobody knows what it is. It is the ultimate "we know it's in here somewhere".
Hands-on activityDraw an ellipse and test the equal-areas law
You need: a sheet of cardboard or a corkboard, a large sheet of paper, two thumbtacks or push pins (handle the points carefully), about 30 cm of string tied in a loop, a pencil, a ruler, graph paper is a bonus.
- Push the two pins into the paper about 8 cm apart. These are the foci. Put the loop of string around them, pull it tight with the pencil, and trace all the way around. You have drawn an ellipse.
- Move the pins to 4 cm apart and draw another. Then put both pins in the same hole and draw a third. What happens to the shape as the foci get closer? (You get a circle when they meet.)
- On the most stretched ellipse, label one pin "Sun". Mark the perihelion and aphelion.
- Draw a thin wedge from the Sun near perihelion and a long thin wedge near aphelion that you estimate have the same area (count squares on graph paper, or use triangle area = ½ × base × height).
- Compare the lengths of orbit each wedge covers. Equal areas mean equal times, so which part of the orbit is covered faster?
What to look for: the closer the foci, the rounder the ellipse. The wedge near perihelion covers a much longer stretch of orbit than the equal-area wedge near aphelion, so the planet must move faster near the Sun. The sum of the distances from any point to the two pins is always the length of string available, which is the definition of an ellipse.
Your turn
1State Kepler's three laws in your own words.
- Planets move in ellipses with the Sun at one focus. 2. A line from the Sun to a planet sweeps out equal areas in equal times (faster when closer). 3. T²/a³ is the same for every planet orbiting the Sun.
2Jupiter's semi-major axis is 5.20 AU. Find its period.
T² = a³ = (5.20)³ = 140.6, so T = 11.9 years.
3An asteroid has a period of 2.00 years. Find its semi-major axis.
a³ = T² = 4.00, so a = ∛4.00 = 1.59 AU.
4Earth's distance from the Sun is 1.471 × 10¹¹ m at perihelion and 1.521 × 10¹¹ m at aphelion. At which point is Earth's speed greater, and in which month does it happen?
At perihelion, in early January (equal areas: closer means faster).
5Phobos orbits Mars with a = 9.38 × 10⁶ m and T = 0.3189 days. Find the mass of Mars.
T = 2.755 × 10⁴ s. M = 4π²a³/(GT²) = 4π²(9.38 × 10⁶)³/((6.67 × 10⁻¹¹)(2.755 × 10⁴)²) = 6.43 × 10²³ kg.
6Explain what a flat galaxy rotation curve tells us.
If speed stays the same far from the centre, then M = v²r/G keeps growing with r. There must be a lot of unseen mass spread far out: dark matter.
More practice: warm-up
1What shape is a planet's orbit?
An ellipse (some are very nearly circles).
2Where is the Sun in a planet's orbit?
At one focus of the ellipse.
3Where does a planet move slowest?
At aphelion, farthest from the Sun.
4Which two quantities does Kepler's third law relate?
The period T and the semi-major axis a (T² ∝ a³).
5What is the name of the black hole at the centre of the Milky Way?
Sagittarius A\* (Sgr A\*).
More practice: on your own
1Saturn's moon Titan orbits with a = 1.222 × 10⁹ m and T = 15.95 days. Find Saturn's mass.
T = 1.378 × 10⁶ s. M = 4π²(1.222 × 10⁹)³/((6.67 × 10⁻¹¹)(1.378 × 10⁶)²) = 5.69 × 10²⁶ kg (about 95 Earth masses).
2Io orbits Jupiter at 4.22 × 10⁸ m with T = 1.769 days. Ganymede orbits at 1.07 × 10⁹ m. Predict Ganymede's period without using G.
T_G = T_I (a_G/a_I)^(3/2) = 1.769 × (1.07 × 10⁹/4.22 × 10⁸)^1.5 = 1.769 × 4.04 = 7.14 days (the measured value is 7.15 days).
3Halley's Comet has a semi-major axis of about 17.8 AU. Find its period.
T = (17.8)^1.5 = 75 years (about 75 to 76 years).
4Why do the moons of Jupiter and the planets of the Sun have different values of T²/a³?
T²/a³ = 4π²/GM depends on the central mass M. Jupiter's mass is about 1/1000 of the Sun's, so its moons have a T²/a³ about 1000 times larger.
5Use M = a³/T² in solar units to estimate the mass of Sagittarius A∗ from S2 (a ≈ 1000 AU, T ≈ 16 years). Why must it be a black hole?
M = 1000³/16² ≈ 3.9 × 10⁶ solar masses. Four million Suns' worth of mass within about 120 AU of it, giving off almost no light, cannot be a star cluster; the best explanation is a black hole.
Challenge
1Show that for any circular orbit, Kepler's third law can be written T²/r³ = 4π²/GM, and use it to calculate T²/r³ for satellites of Earth.
GMm/r² = m(4π²r/T²) (centripetal acceleration 4π²r/T²). Rearranged: T²/r³ = 4π²/GM. For Earth: 4π²/((6.67 × 10⁻¹¹)(5.97 × 10²⁴)) = 9.91 × 10⁻¹⁴ s²/m³, the same for the Moon, the ISS and every Earth satellite.
2If all the Milky Way's mass inside 26 000 light-years were concentrated there and there were no more mass beyond it, what orbital speed would you expect at 52 000 light-years? Measured speeds there are still about 200 to 230 km/s. What does this suggest?
v ∝ 1/√r with M fixed: v = 230/√2 ≈ 163 km/s. Measured speeds are much higher, so there must be extra mass beyond 26 000 light-years that we cannot see: evidence for dark matter.
3Earth's orbital speed is 30.3 km/s at perihelion (1.471 × 10¹¹ m). Use the equal-areas law (r × v is constant at the two ends of the orbit) to find its speed at aphelion (1.521 × 10¹¹ m).
r_p v_p = r_a v_a, so v_a = (1.471/1.521)(30.3) = 29.3 km/s. About 1 km/s slower in July than in January.
Check your understandingQuiz
1. According to Kepler's first law, the Sun is located
2. A planet moves fastest when it is
3. A planet has a semi-major axis of 4.0 AU. Its period is
4. The constant in T²/a³ = 4π²/GM depends on
5. Flat galaxy rotation curves are evidence for
6. Astronomers found the mass of Sagittarius A∗ mainly by
7. Earth is closest to the Sun in
For parents and teachersBig idea (D2.2): Kepler's laws describe orbits, and Newton's gravitation explains them. The third law, T²/a³ = 4π²/GM, lets astronomers measure mass from motion: planets, black holes and whole galaxies, and it reveals dark matter.
How to help: Do the string-and-pins ellipse together; it is quick and memorable. Ask your teen to explain why Earth moves fastest in January, and how astronomers know Sagittarius A∗ is a black hole without seeing it.
Common difficulties:
- Using T² = a³ for moons of Jupiter or Earth satellites. It only works in years and AU for objects orbiting the Sun; otherwise use T² = 4π²a³/GM with SI units.
- Mixing up which mass is found: Kepler's third law finds the central mass, not the orbiting one.
- Thinking dark matter is the same as black holes. Black holes are made of ordinary matter that collapsed; dark matter is something else, not yet identified.
Safety: push pins are sharp; supervise younger siblings.