D. Gravitational, Electric, and Magnetic Fields · Gravitational, Electric and Magnetic FieldsSatellites and Circular Orbits
D2.2 D2.1 D1.2About 75 minutes
Learning goals- I can explain why a satellite in orbit is in free fall, using Newton's cannon.
- I can set the gravitational force equal to the centripetal force and derive v = √(GM/r) and T = 2π√(r³/GM).
- I can calculate the speed, period and radius of satellite orbits, including geostationary and GPS orbits.
- I can explain apparent weightlessness on the International Space Station.
Words to know
satellite
An object that orbits a larger body. The Moon is a natural satellite; the ISS and GPS satellites are artificial satellites.
orbital speed
The speed a satellite needs to stay in a circular orbit of radius r: v = √(GM/r).
period (T)
The time for one complete orbit, in seconds (s).
geostationary orbit
A circular orbit above the equator with a period of one sidereal day (about 23 h 56 min), so the satellite stays above the same spot on Earth. Its altitude is about 35 800 km.
low Earth orbit (LEO)
An orbit up to about 2000 km above Earth's surface, used by the ISS and many Earth-observation satellites.
apparent weightlessness
The feeling of having no weight when you and everything around you are in free fall together, so nothing pushes up on you.
Falling around the world
The International Space Station circles Earth about every 93 minutes, at a speed of nearly 7.7 km/s. Canadian astronauts such as Chris Hadfield and David Saint-Jacques have lived on it for months, floating in the cabin. In April 2026, Canadian Space Agency astronaut Jeremy Hansen flew around the Moon on Artemis II, the first crewed lunar mission since Apollo, splashing down on April 10, 2026. Every one of those trips is planned with the physics in this lesson.
Remember from the Dynamics unit: an object moving in a circle of radius r at constant speed v has a centripetal acceleration a_c = v²/r = 4π²r/T² toward the centre, and it needs a net force F_c = mv²/r toward the centre. For a satellite, that force is gravity.
Newton's cannon
Newton imagined a cannon on a very tall mountain, above the air, firing horizontally.
- A slow cannonball curves down and lands nearby (A).
- A faster one lands farther away (B, C).
- Earth's surface curves away beneath a moving object: over a horizontal distance of 7.9 km, the ground drops about 4.9 m below a straight line. A ball launched horizontally falls 4.9 m in its first second. So if it moves at about 7.9 km/s (just above the surface, ignoring air), the ground curves away exactly as fast as the ball falls. It keeps falling and keeps missing the ground. It is in orbit (D).
So an orbit is not an escape from gravity. It is free fall with enough sideways speed.
Newton's cannon. The faster the horizontal launch, the farther the ball lands, until at about 7.9 km/s the ground curves away as fast as the ball falls: the ball is in orbit.The orbit equations
For a satellite of mass m in a circular orbit of radius r around a planet of mass M, gravity provides the centripetal force:
GMm/r² = mv²/r
Cancel m and one r:
v = √(GM/r)
The time for one orbit is the circumference divided by the speed, T = 2πr/v. Substituting v:
T = 2π√(r³/GM), or equivalently T² = (4π²/GM) r³
Three things to notice:
- The satellite's mass m cancels. A wrench and a space station at the same r orbit at the same speed. That is why a tool let go during a spacewalk drifts alongside the astronaut.
- Lower orbits are faster. Smaller r gives larger v and shorter T.
- For a given planet, r fixes everything: choosing an orbit radius fixes its speed and period.
In a circular orbit the velocity is tangent to the circle and the gravitational force points to the centre. Gravity changes the direction of the velocity, not its size.Worked exampleExample 1: The ISS
The ISS orbits about 420 km above Earth's surface. Find its orbital speed and period. (M_E = 5.97 × 10²⁴ kg, R_E = 6.37 × 10⁶ m)
- r = R_E + h = 6.37 × 10⁶ + 4.2 × 10⁵ = 6.79 × 10⁶ m.
- v = √(GM/r) = √((6.67 × 10⁻¹¹)(5.97 × 10²⁴)/(6.79 × 10⁶)) = √(5.864 × 10⁷) = 7.66 × 10³ m/s.
- T = 2πr/v = 2π(6.79 × 10⁶)/(7.66 × 10³) = 5.57 × 10³ s.
- Convert: 5.57 × 10³ s ÷ 60 = 92.8 min.
v ≈ 7.66 km/s (about 27 600 km/h) and T ≈ 93 min. The crew sees about 15 or 16 sunrises a day.
Worked exampleExample 2: Geostationary orbit
A communications satellite must stay above the same point on the equator, so its period must equal Earth's rotation period, one sidereal day = 86 164 s (23 h 56 min 4 s). Find its orbital radius, altitude and speed.
- Rearrange T² = 4π²r³/GM: r = ∛(GMT²/4π²).
- GM = (6.67 × 10⁻¹¹)(5.97 × 10²⁴) = 3.982 × 10¹⁴ m³/s².
- r = ∛((3.982 × 10¹⁴)(86 164)²/(4π²)) = ∛(7.489 × 10²²) = 4.216 × 10⁷ m.
- Altitude = r − R_E = 4.216 × 10⁷ − 0.637 × 10⁷ = 3.58 × 10⁷ m (35 800 km).
- v = 2πr/T = 2π(4.216 × 10⁷)/86 164 = 3.07 × 10³ m/s.
r ≈ 4.22 × 10⁷ m, altitude ≈ 35 800 km, v ≈ 3.07 km/s. Every geostationary satellite in the world shares this one ring above the equator, so positions in it are assigned by international agreement.
Sidereal day
Why one sidereal day, not 24 h? Earth turns once relative to the distant stars in about 23 h 56 min. The extra 4 min in a 24 h solar day is needed because Earth also moves along its orbit around the Sun. Using 24 h gives almost the same radius (4.22 × 10⁷ m), so either is fine for most problems, but say which you used.
Three working orbits drawn to scale. The ISS skims just above Earth. GPS satellites orbit about 20 200 km up, twice a day. Geostationary satellites orbit 35 800 km up, once a day.Apparent weightlessness
On the ISS, g is still 8.6 N/kg. So why do astronauts float?
Your weight is the gravitational force on you. What you feel as weight is the normal force: the floor pushing up on you. On the ISS, the astronaut, the floor and the whole station are all falling toward Earth with the same acceleration (all at g = 8.6 m/s²). The floor never has to push the astronaut, so the normal force is zero. The astronaut feels weightless, even though gravity is pulling on them with about 88% of their Earth weight. This is apparent weightlessness.
You get the same feeling for a moment at the top of a drop ride, or when an elevator starts down quickly. Long stays in apparent weightlessness weaken bones and muscles, which is why astronauts exercise about two hours a day.
Orbits Canada uses
- Low Earth orbit: the ISS (about 400 to 420 km), where Canada's robotic arm Canadarm2 works, and the three RADARSAT Constellation Mission satellites (about 600 km, launched in 2019), which use radar to monitor sea ice, ships, floods and land.
- Medium Earth orbit: the GPS constellation, about 31 operational satellites (the exact count changes as new ones launch and old ones retire) in six orbital planes about 20 200 km up, each circling Earth twice a day.
- Geostationary orbit: TV, internet and weather satellites over the equator. From southern Canada they sit in the southern sky. In the far North they are low on the horizon or below it, which makes satellite service there harder.
You will look at how satellites affect society and the environment in the lesson Fields, Technology and Society.
Worked exampleExample 3: How high for a 90-minute orbit?
A space agency wants a satellite in a circular orbit with a period of exactly 90.0 min. At what altitude must it orbit?
- T = 90.0 × 60 = 5400 s.
- r = ∛(GMT²/4π²) = ∛((3.982 × 10¹⁴)(5400)²/(4π²)) = ∛(2.941 × 10²⁰) = 6.65 × 10⁶ m.
- Altitude = 6.65 × 10⁶ − 6.37 × 10⁶ = 2.8 × 10⁵ m.
About 280 km above the surface. Orbits this low last only a short time because the thin upper atmosphere drags on the satellite.
Just for funAstronauts on the ISS are not in zero gravity. They are falling toward Earth about 16 times a day and missing every time. Physics calls this an orbit; a skateboarder would call it the longest fall ever.
Hands-on activitySwing a model satellite
You need: a small soft ball or a rolled pair of socks, about 1 m of strong string, a hollow tube (an empty pen barrel with the ink removed, or a short piece of plastic straw from a sturdy smoothie straw), several washers or large paper clips as a counterweight, tape, a stopwatch. Do this outside or in a large room, away from people and windows; wear safety glasses if you have them.
- Tie the soft ball to one end of the string. Thread the string through the tube and tie the washers to the other end. The washers' weight is the "gravity" that pulls the ball toward the centre.
- Hold the tube and swing the ball in a horizontal circle above your head, adjusting the speed until the string length (the orbit radius) stays steady. Mark the string just below the tube with a bit of tape so you can see if r changes.
- Time 10 orbits and find T. Measure r.
- Keep the same counterweight, but use a shorter radius. Are you forced to swing faster or slower to hold it steady?
What to look for: with the same central pull, a smaller orbit needs a shorter period (more circles per second), just as low satellites orbit faster than high ones. (In this model the central force is fixed, while in real orbits gravity gets stronger closer in, so the numbers are different, but the trend is the same.)
Your turn
1Explain in two sentences why a satellite in orbit does not fall to Earth.
It is falling toward Earth all the time, because gravity pulls it toward the centre. But it also moves sideways so fast that Earth's surface curves away beneath it as fast as it falls, so it never gets closer.
2Derive v = √(GM/r) for a circular orbit.
Gravity is the centripetal force: GMm/r² = mv²/r. Cancel m and multiply both sides by r: GM/r = v². Take the square root: v = √(GM/r).
3Find the speed and period of a satellite orbiting 1000 km above Earth's surface.
r = 7.37 × 10⁶ m. v = √((3.982 × 10¹⁴)/(7.37 × 10⁶)) = 7.35 × 10³ m/s. T = 2π(7.37 × 10⁶)/(7.35 × 10³) = 6.30 × 10³ s ≈ 105 min.
4A RADARSAT Constellation satellite orbits about 600 km above Earth. Find its period.
r = 6.97 × 10⁶ m. v = √(3.982 × 10¹⁴/6.97 × 10⁶) = 7.56 × 10³ m/s. T = 2πr/v = 5.79 × 10³ s ≈ 96.6 min.
5Use the Moon's orbit (r = 3.84 × 10⁸ m) to predict its period in days. Compare with the measured 27.3 days.
T = 2π√(r³/GM) = 2π√((3.84 × 10⁸)³/3.982 × 10¹⁴) = 2.37 × 10⁶ s = 27.4 days. Very close to 27.3 days; the small difference is because Earth and the Moon both orbit their common centre of mass.
6Why does an astronaut float in the ISS even though g there is about 8.6 N/kg?
The astronaut and the station are both in free fall with the same acceleration, so the floor does not need to push on the astronaut. The normal force (the force we feel as weight) is zero: apparent weightlessness.
More practice: warm-up
1What force provides the centripetal force for a satellite?
Gravity (the gravitational force from the planet).
2Does a heavier satellite need to go faster to stay in the same orbit?
No. The satellite's mass cancels in v = √(GM/r).
3Which orbits faster: a satellite at 400 km or one at 36 000 km?
The one at 400 km (lower orbits are faster).
4What is the period of a geostationary satellite?
One sidereal day, about 23 h 56 min (about 24 h).
5About how high do GPS satellites orbit, and how many times a day do they circle Earth?
About 20 200 km up, twice a day.
More practice: on your own
1A satellite orbits at r = 2R_E (one Earth radius above the surface). Find its speed and period.
r = 1.274 × 10⁷ m. v = √(3.982 × 10¹⁴/1.274 × 10⁷) = 5.59 × 10³ m/s. T = 2πr/v = 1.43 × 10⁴ s ≈ 3.98 h.
2A space probe orbits Mars (M = 6.42 × 10²³ kg, R = 3.39 × 10⁶ m) 400 km above the surface. Find its speed and period.
r = 3.79 × 10⁶ m. v = √((6.67 × 10⁻¹¹)(6.42 × 10²³)/3.79 × 10⁶) = 3.36 × 10³ m/s. T = 2πr/v = 7.08 × 10³ s ≈ 118 min.
3Find the centripetal (gravitational) force on a 1500 kg geostationary satellite (r = 4.22 × 10⁷ m).
F = GMm/r² = (3.982 × 10¹⁴)(1500)/(4.22 × 10⁷)² = 335 N. (Its weight on the ground would be about 14 700 N.)
4The Moon has a period of 27.3 days and orbital radius 3.84 × 10⁸ m. Use these to calculate Earth's mass.
M = 4π²r³/(GT²). T = 27.3 × 86 400 = 2.359 × 10⁶ s. M = 4π²(3.84 × 10⁸)³/((6.67 × 10⁻¹¹)(2.359 × 10⁶)²) = 6.02 × 10²⁴ kg (close to the accepted 5.97 × 10²⁴ kg).
5If a satellite moves to an orbit with 4 times the radius, by what factor do its speed and period change?
v ∝ 1/√r: speed is 1/2 as large. T ∝ r^(3/2): period is 4^(3/2) = 8 times as long.
Challenge
1Show that the period of a satellite skimming the surface of any planet depends only on the planet's density ρ: T = √(3π/(Gρ)).
T² = 4π²R³/(GM) and M = ρ(4/3)πR³. Then T² = 4π²R³/(G ρ (4/3)πR³) = 3π/(Gρ). So T = √(3π/(Gρ)): R cancels, only the density matters.
2Use Earth's orbit (r = 1.50 × 10¹¹ m, T = 365.25 days) to find the mass of the Sun.
T = 3.156 × 10⁷ s. M = 4π²r³/(GT²) = 4π²(1.50 × 10¹¹)³/((6.67 × 10⁻¹¹)(3.156 × 10⁷)²) = 2.01 × 10³⁰ kg.
3An astronaut on the ISS lets go of a 2 kg wrench in front of her. Describe the wrench's motion as seen by her and as seen from the ground, and explain using v = √(GM/r).
From the ground, the wrench keeps moving at about 7.66 km/s in (almost) the same orbit, because orbital speed depends only on r, not mass. To the astronaut, who is in the same orbit, the wrench appears to float in place (or drift slowly if she gave it a small push). Both are free-falling around Earth together.
Check your understandingQuiz
1. For a satellite in a circular orbit, the centripetal force is provided by
2. Two satellites, 500 kg and 2000 kg, orbit Earth at the same radius. Compared with the 500 kg satellite, the 2000 kg one moves
3. Which change makes a satellite's orbital period longer?
4. An astronaut floats inside the ISS mainly because
5. A geostationary satellite must orbit
6. If a satellite's orbital radius is quadrupled, its orbital speed
For parents and teachersBig idea (D2.2): an orbit is free fall with enough sideways speed. Setting gravity equal to the centripetal force (GMm/r² = mv²/r) gives v = √(GM/r) and T = 2π√(r³/GM).
How to help: Ask your teen to explain Newton's cannon in their own words, then to say whether low or high satellites are faster and why. Check calculations by confirming the ISS answer (about 93 minutes), which is easy to look up.
Common difficulties:
- Using altitude instead of r = R_E + altitude.
- Unit slips with T: convert hours or days to seconds before using the formula.
- Believing there is no gravity in orbit. The field is weaker, not zero; astronauts float because they are falling.
- Cube roots: on most calculators use the x^(1/3) or ∛ key.
Safety for the activity: swing the soft ball away from people, pets and windows, and use only a soft object.