Grade by Grade
B. Organic Chemistry · Organic Chemistry

Reactions of Hydrocarbons: Combustion, Substitution and Addition

B3.3 B2.4 B2.2 A1.4 A1.10About 75 minutes
Learning goals
  • I can write balanced equations for complete and incomplete combustion of hydrocarbons.
  • I can describe substitution reactions of alkanes and of benzene.
  • I can predict the products of addition reactions of alkenes and alkynes (H₂, halogens, hydrogen halides and water), using Markovnikov's rule.
  • I can describe how bromine water or potassium permanganate distinguishes saturated, unsaturated and aromatic hydrocarbons, and the safety precautions involved.

Words to know

combustion
A rapid reaction with oxygen that releases energy; complete combustion of a hydrocarbon gives CO₂ and H₂O.
substitution reaction
A reaction in which an atom or group on a molecule is replaced by another atom or group.
addition reaction
A reaction in which atoms add across a double or triple bond, which becomes a single (or double) bond; there is one product.
hydrogenation
Addition of H₂ to a multiple bond, using a metal catalyst such as Pt, Pd or Ni.
halogenation
Adding a halogen (Cl₂, Br₂) to a molecule, by addition (alkenes) or substitution (alkanes, benzene).
hydration
Addition of water (H and OH) across a C=C bond to make an alcohol, using an acid catalyst.
Markovnikov's rule
When HX or H₂O adds to an unsymmetrical alkene, the H goes to the double-bond carbon that already has more H atoms.
WHMIS
Workplace Hazardous Materials Information System: Canada's system of hazard pictograms, labels and safety data sheets (SDS).

What hydrocarbons do

Alkanes are sometimes called paraffins, from Latin words meaning "little affinity", because they react with very little at room temperature. Alkenes and alkynes are far more reactive: their double and triple bonds are rich in electrons and easy to attack. This lesson covers the four big reaction types of hydrocarbons:

  1. Combustion (all hydrocarbons)
  2. Substitution (alkanes and aromatics)
  3. Addition (alkenes and alkynes)
  4. Tests that use these differences to identify an unknown

Remember from Grade 11: in Chemical Reactions you balanced combustion equations and compared complete and incomplete combustion. We start there.

1. Combustion

Complete combustion (plenty of oxygen) gives carbon dioxide and water:

C₃H₈ + 5 O₂ → 3 CO₂ + 4 H₂O

Incomplete combustion (limited oxygen) also gives carbon monoxide (CO) and soot (C):

2 CH₄ + 3 O₂ → 2 CO + 4 H₂O

Carbon monoxide is colourless, odourless and deadly, because it binds to hemoglobin in place of oxygen. That is why Ontario law requires carbon monoxide alarms in homes with a fuel-burning appliance, a fireplace or an attached garage, and why you should never run a generator, barbecue or car in a closed space.

Worked example

Example 1: Balancing complete combustion

Write the balanced equation for the complete combustion of octane, C₈H₁₈.

  1. Unbalanced: C₈H₁₈ + O₂ → CO₂ + H₂O.
  2. Balance C: 8 CO₂. Balance H: 18 H → 9 H₂O.
  3. Count O on the right: 16 + 9 = 25 O atoms, so 12.5 O₂.
  4. Double everything to clear the fraction.

2 C₈H₁₈ + 25 O₂ → 16 CO₂ + 18 H₂O

2. Substitution

Alkanes react with chlorine or bromine only when energy is supplied as ultraviolet light (or high heat). One H atom is replaced by a halogen atom, and the H leaves with the other halogen atom as HX:

CH₄ + Cl₂ —(UV light)→ CH₃Cl + HCl

The reaction does not stop neatly. CH₃Cl can react again to give CH₂Cl₂, CHCl₃ and CCl₄, and larger alkanes give mixtures of position isomers, so this is a messy way to make one pure product.

Benzene also undergoes substitution, not addition, because addition would destroy its stable ring of delocalized electrons. It needs a catalyst such as FeBr₃:

C₆H₆ + Br₂ —(FeBr₃)→ C₆H₅Br + HBr

How to recognize a substitution: two reactants → two products, and one of the products is usually a small molecule such as HCl or HBr.

3. Addition to alkenes and alkynes

In an addition reaction, the double bond opens and one new atom bonds to each carbon of the former double bond. Two reactants → one product. The four main additions are:

  • Hydrogenation, H₂: metal catalyst (Pt, Pd or Ni) → alkane. CH₂=CH₂ + H₂ → CH₃CH₃
  • Halogenation, Br₂ or Cl₂: room temperature → dihaloalkane. CH₂=CH₂ + Br₂ → CH₂BrCH₂Br
  • Hydrohalogenation, HCl or HBr: → haloalkane. CH₂=CH₂ + HBr → CH₃CH₂Br
  • Hydration, H₂O: acid catalyst (H₂SO₄) → alcohol. CH₂=CH₂ + H₂O → CH₃CH₂OH (This is how much industrial ethanol is made.)

An alkyne can add twice: the triple bond becomes a double bond, then a single bond.

HC≡CH + 2 H₂ —(Pt)→ CH₃CH₃

CCHHHHethene+BrBrbromineCCHHHHBrBr1,2-dibromoethaneC=C double bondone Br added to each carbonthe double bond opens; two atoms add; nothing is left over
Addition of bromine to ethene. The two carbons of the double bond each gain one bromine atom, and the double bond becomes a single bond. Two reactants make one product.

Markovnikov's rule

When H–Br adds to a symmetrical alkene such as ethene or but-2-ene, there is only one possible product. But propene is unsymmetrical: the H could go to C1 or to C2. Experiments show that one product strongly dominates. The Russian chemist Vladimir Markovnikov summarized the pattern in 1869:

When HX or H–OH adds to an unsymmetrical alkene, the H atom goes to the double-bond carbon that already has more H atoms, and the X (or OH) goes to the other carbon.

So propene + HBr gives mainly 2-bromopropane, and propene + H₂O gives mainly propan-2-ol. In university organic chemistry you will learn the reason: the reaction passes through a positively charged intermediate, and a positive charge on the more substituted carbon is more stable.

CH₃CHCH₂C2: 1 HC1: 2 Hpropene + H–BrCH₃CHCH₃Br2-bromopropanemajor productCH₃CH₂CH₂Br1-bromopropane (minor)H goes to the double-bond carbon that already has more H
Markovnikov's rule for propene + HBr. C1 already has two H atoms and C2 has one, so the new H goes to C1 and the Br to C2. The main product is 2-bromopropane.
Worked example

Example 2: Predicting addition products

Give the structure and name of the main product: (a) but-2-ene + H₂ (Ni); (b) propene + HCl; (c) 2-methylpropene + H₂O (H₂SO₄ catalyst).

  1. (a) Symmetrical; each C of the double bond gains an H: CH₃CH₂CH₂CH₃, butane.
  2. (b) CH₂=CH–CH₃: C1 has 2 H, C2 has 1 H. H goes to C1, Cl to C2: CH₃CHClCH₃, 2-chloropropane.
  3. (c) CH₂=C(CH₃)₂: C1 has 2 H, C2 has none. H goes to C1, OH to C2: (CH₃)₃COH, 2-methylpropan-2-ol.

(a) butane, (b) 2-chloropropane, (c) 2-methylpropan-2-ol.

Worked example

Example 3: An alkyne adds twice

Write the equation for but-1-yne reacting with excess bromine. Name the product.

  1. HC≡C–CH₂CH₃ has a triple bond, so it can add two Br₂ molecules.
  2. Each carbon of the triple bond ends up with two Br atoms.
  3. Product: CHBr₂–CBr₂–CH₂CH₃.

HC≡CCH₂CH₃ + 2 Br₂ → CHBr₂CBr₂CH₂CH₃, 1,1,2,2-tetrabromobutane.

Worked example

Example 4: Substitution or addition?

Classify each: (a) C₂H₆ + Br₂ → C₂H₅Br + HBr (UV light); (b) C₃H₆ + Br₂ → C₃H₆Br₂; (c) C₆H₆ + Cl₂ → C₆H₅Cl + HCl (FeCl₃).

  1. (a) Two products, an H replaced by Br, HBr formed → substitution (alkane).
  2. (b) One product containing all the atoms of both reactants → addition (alkene).
  3. (c) Two products, ring H replaced by Cl → substitution (aromatic).

(a) substitution, (b) addition, (c) substitution.

4. Testing for unsaturation: a lab you can describe

In a school lab, a few drops of a hydrocarbon are added to bromine water, which is orange-brown.

  • An alkene or alkyne decolourizes it immediately: the Br₂ adds across the multiple bond and is used up.
  • An alkane gives no change in the dark. (In bright sunlight it slowly reacts by substitution.)
  • Benzene gives no change: without a catalyst, it does not react.

Potassium permanganate solution is another test: an alkene turns the purple solution brown (a brown precipitate of MnO₂ forms), while alkanes and benzene leave it purple.

Safety (A1.4): bromine water is toxic and corrosive, and its vapour irritates the lungs. The test is done in a fume hood, with safety goggles, gloves and a lab coat. Hydrocarbons such as hexane and cyclohexene are flammable: no open flames in the room. Check the WHMIS label and the safety data sheet (SDS) for each chemical before you begin, and pour all organic waste into the labelled waste container, never down the sink. Do not try this test at home.

alkaneno change (dark)alkenedecolourized at oncebenzeneno changeStart: each tube hasorange-brown brominewater and a few dropsof the hydrocarbon.
Results of the bromine-water test. Only the unsaturated hydrocarbon (an alkene) removes the orange-brown colour at once; the alkane and benzene do not react under these conditions.

Addition in your kitchen: hydrogenation and trans fats

Vegetable oils are liquids because their long carbon chains contain cis C=C bonds, which put kinks in the chains so they cannot pack closely. Adding H₂ with a nickel catalyst (hydrogenation) converts some C=C bonds to C–C bonds, so the chains straighten and the fat becomes solid, like shortening or hard margarine.

Partial hydrogenation has a side effect: some of the remaining double bonds flip from cis to trans. Trans fats raise the risk of heart disease, so Canada banned partially hydrogenated oils in foods in September 2018. This is a real example of B1: understanding an organic reaction helped shape a public health law.

Hands-on activity

Watching combustion with a candle

You need: a tea light or short candle in a holder, a metal spoon, a clear glass jar (heat-resistant, such as a canning jar), a plate, matches or a lighter, and a grown-up. Grown-up note: an adult should light the candle and stay for the whole activity. Work on a non-flammable surface, tie back long hair, keep a damp cloth nearby, and let the spoon and jar cool before touching them.

  1. Light the candle. Candle wax is a mixture of large alkanes (paraffin, about C₂₀ to C₄₀).
  2. Using an oven mitt, hold the back of the cold spoon in the tip of the flame for 3 seconds. Look at the spoon. What is the black deposit?
  3. Hold the cold, dry jar upside down about 10 cm above the flame for 5 seconds. Look inside it.
  4. Place the jar over the candle on the plate. Time how long the flame lasts.
  5. Write a word equation and a balanced equation for complete combustion of C₂₅H₅₂, a typical wax alkane.

What to look for: the spoon collects soot (carbon): incomplete combustion where the spoon cools the flame and blocks oxygen. The jar fogs with water, a product of combustion. Under the jar the flame goes out once the oxygen is used up. Balanced equation: C₂₅H₅₂ + 38 O₂ → 25 CO₂ + 26 H₂O.

Just for fun

Students often remember Markovnikov's rule as "the rich get richer": the carbon that is already rich in hydrogen atoms gets the new one. It is the only time chemists approve of hydrogen hoarding.

Your turn

1

Balance the complete combustion of ethane, C₂H₆.

2

What two products of incomplete combustion are not formed in complete combustion?

3

Complete: CH₃CH₃ + Cl₂ —(UV)→ ? + ?. Name the organic product and the reaction type.

4

Give the product of propene + H₂ (Pt catalyst).

5

Give the main product of but-1-ene + HBr.

6

Name the product of cyclohexene + Br₂.

7

A liquid decolourizes bromine water immediately. What does that tell you?

More practice: warm-up

1

What are the products of the complete combustion of any hydrocarbon?

2

What type of reaction turns an alkene into an alkane?

3

What catalyst is used in hydrogenation?

4

What does an alkane need to react with Cl₂?

5

Which kind of hydrocarbon undergoes substitution with Br₂ only when FeBr₃ is present?

More practice: on your own

1

Predict the main product of hydration of propene and name it.

2

Write a balanced equation for incomplete combustion of propane that produces CO and H₂O only.

3

Which alkene would you start with to make 2-chlorobutane by addition of HCl, so that only one product is possible?

4

How many moles of H₂ can one mole of buta-1,3-diene add? Name the final product.

5

Explain why benzene does not decolourize bromine water, even though its formula suggests three double bonds.

Challenge

1

A hydrocarbon X, C₅H₁₀, decolourizes bromine water. Hydrogenation of X gives 2-methylbutane. Applying Markovnikov's rule, hydration of X is predicted to give 3-methylbutan-2-ol, CH₃CH(OH)CH(CH₃)₂, as the main product. Identify X.

2

Bromine water test: 2.00 g of a sample of cyclohexene (C₆H₁₀, 82.14 g/mol) is mixed with excess bromine. What mass of Br₂ (159.80 g/mol) reacts?

3

A student proposes making pure 2-chlorobutane by reacting butane with Cl₂ in UV light. Evaluate the plan and suggest a better one.

Check your understanding

Quiz

1.

Which equation shows an addition reaction?

2.

What is the main product when HCl adds to propene?

3.

Which compound decolourizes bromine water immediately at room temperature?

4.

What condition is needed for methane to react with chlorine?

5.

Which product forms in incomplete but NOT in complete combustion?

6.

Why did Canada ban partially hydrogenated oils in 2018?

7.

Which safety step is essential when doing the bromine-water test?

For parents and teachers

Big ideas (B3.3, B2.4): alkanes burn and undergo substitution (with UV light); alkenes and alkynes undergo addition; benzene undergoes substitution with a catalyst. Markovnikov's rule predicts the main product when HX or water adds to an unsymmetrical alkene.

How to help: Ask your teen to sort reactions by counting: "two reactants → one product" is addition; "two → two, with HX" is substitution. Ask them to explain the bromine-water results.

Common difficulties:

  • Putting the H on the wrong carbon (Markovnikov's rule).
  • Writing alkanes undergoing addition (they have no multiple bond).
  • Forgetting that alkynes can add two molecules.
  • Fractions in combustion equations: double all coefficients.

Safety: the candle activity needs an adult present the whole time. The bromine-water and permanganate tests are school-lab procedures only. Make sure your home has a working carbon monoxide alarm.