B. Organic Chemistry · Organic ChemistryAlkenes and Alkynes: Naming Unsaturated Hydrocarbons
B2.2 B2.1 B3.1 B3.5About 70 minutes
Learning goals- I can write general formulas for alkenes (CₙH₂ₙ) and alkynes (CₙH₂ₙ₋₂).
- I can name and draw alkenes, alkynes and cycloalkenes, including those with branches.
- I can explain why some alkenes have cis and trans isomers, and name them.
- I can describe where alkenes and alkynes are found and used.
Words to know
alkene
A hydrocarbon with at least one carbon-carbon double bond; with one double bond and no ring, the formula is CₙH₂ₙ.
alkyne
A hydrocarbon with at least one carbon-carbon triple bond; with one triple bond and no ring, the formula is CₙH₂ₙ₋₂.
diene
A hydrocarbon with two C=C double bonds, such as buta-1,3-diene.
stereoisomers
Molecules with the same atoms bonded in the same order but arranged differently in space.
cis-trans (geometric) isomers
Stereoisomers that differ in which side of a C=C double bond (or ring) the groups are on. Cis: same side; trans: opposite sides.
cycloalkene
A ring hydrocarbon that contains a C=C double bond, such as cyclohexene (C₆H₁₀).
Double and triple bonds
A ripening banana gives off a tiny amount of ethene gas (also called ethylene), a plant hormone that tells nearby fruit to ripen. Put a green banana in a paper bag with a ripe one and it ripens faster. Ethene is also one of the most-produced organic chemicals in the world, because it is the starting material for polyethylene plastic.
Ethene is an alkene: a hydrocarbon with a C=C double bond. Its cousin ethyne (acetylene), HC≡CH, is an alkyne, with a C≡C triple bond. It burns with oxygen in an extremely hot flame, hot enough to cut and weld steel.
Both families are unsaturated. Each double bond removes 2 H atoms compared with the alkane, and each triple bond removes 4:
- alkanes CₙH₂ₙ₊₂ (ethane C₂H₆)
- alkenes CₙH₂ₙ (ethene C₂H₄)
- alkynes CₙH₂ₙ₋₂ (ethyne C₂H₂)
Notice that alkenes and cycloalkanes share the formula CₙH₂ₙ. The formula alone does not tell you whether a molecule has a double bond or a ring.
Naming alkenes and alkynes
The rules are the alkane rules with three changes:
- The parent chain is the longest chain that contains the double or triple bond.
- Number the chain from the end nearer the multiple bond, even if a branch then gets a higher number. The multiple bond takes priority over branches.
- Change the ending to -ene (double) or -yne (triple), and give the locant of the first carbon of the multiple bond.
Where does the number go? The current IUPAC style puts it just before the ending: but-2-ene, pent-1-yne, 2-methylbut-1-ene. Many textbooks and labels still use the older style with the number in front: 2-butene, 1-pentyne. Both mean the same molecule and both are accepted in this course.
- Two double bonds: -diene, with an "a" added to the root for easier saying: buta-1,3-diene (1,3-butadiene).
- Ethene, propene, ethyne and propyne need no number: there is only one place the multiple bond can be.
- Cycloalkenes: the double-bond carbons are always C1 and C2, so cyclohexene needs no number. Number through the double bond so that substituents get the lowest locants: 3-methylcyclohexene.
Skeletal structures of four C₄ hydrocarbons. In but-1-ene the double bond starts at C1; in but-2-ene it starts at C2. In but-1-yne the carbons of the triple bond and their neighbours lie in a straight line (180°). The older names are in brackets.Number from the end nearer the double bond. Numbering from the left (bold numbers, marked ✓), the double bond starts at C2 and the methyl is on C4. From the right it would start at C3, so the left-hand numbering wins, even though the methyl gets a higher number.Worked exampleExample 1: A simple alkene
- The chain has 5 carbons and contains the double bond: pent-.
- From the left, the double bond is between C2 and C3; from the right, between C3 and C4. Use the left: locant 2.
- Ending: -ene.
pent-2-ene (2-pentene). It has cis and trans forms; see below.
Worked exampleExample 2: A branched alkene
- Longest chain containing the C=C: CH₂=C–CH₂–CH₃, 4 carbons: but-.
- Number from the double-bond end: the C=C starts at C1.
- The methyl is on C2.
2-methylbut-1-ene (2-methyl-1-butene).
Worked exampleExample 3: An alkyne with a branch
Name HC≡CCH(CH₃)CH₃ and draw its skeletal structure in words.
- Longest chain with the triple bond: HC≡C–CH–CH₃, 4 carbons: but-.
- Number from the triple-bond end: C≡C starts at C1; the methyl is on C3.
- Skeletal: a straight segment of three carbons (C1≡C2–C3, linear), then from C3 two lines go out to the two CH₃ ends.
3-methylbut-1-yne (3-methyl-1-butyne), C₅H₈.
Cis and trans isomers
You saw in Lesson 1 that a double bond cannot rotate. That has a surprising result. In but-2-ene, each carbon of the C=C carries one H and one CH₃. The two CH₃ groups can be on the same side of the double bond (cis) or on opposite sides (trans). These are two different compounds with different boiling and melting points, and you cannot turn one into the other without breaking the π part of the double bond.
Molecules like these, with the same atoms joined in the same order but arranged differently in space, are stereoisomers. Cis and trans isomers are also called geometric isomers.
Test: an alkene has cis and trans forms only if each carbon of the double bond has two different groups attached.
- But-2-ene: C2 has H and CH₃; C3 has H and CH₃ → yes.
- But-1-ene: C1 has H and H (the same) → no.
- 2-methylbut-2-ene: C2 has CH₃ and CH₃ (the same) → no.
Put the prefix cis- or trans- in front of the name: cis-but-2-ene. In university you will also meet the more general E/Z system, which works for any groups.
Cis and trans isomers of but-2-ene. Picture a line through the double bond: in the cis isomer both CH₃ groups are above it; in the trans isomer one is above and one is below. Cis-but-2-ene boils at about 4 °C and trans-but-2-ene at about 1 °C.Worked exampleExample 4: Can it have cis and trans forms?
Decide whether each compound has cis/trans isomers: (a) pent-2-ene, (b) propene, (c) 1,2-dichloroethene.
- (a) CH₃–CH=CH–CH₂CH₃: C2 has H and CH₃; C3 has H and CH₂CH₃. Both carbons have two different groups → yes.
- (b) CH₂=CH–CH₃: C1 has two H → no.
- (c) ClCH=CHCl: each carbon has H and Cl → yes: cis-1,2-dichloroethene and trans-1,2-dichloroethene.
(a) yes, (b) no, (c) yes.
Properties and uses
Alkenes and alkynes are non-polar, like alkanes, so their boiling points are similar to alkanes of the same size, and they do not dissolve in water. The big difference is reactivity. A double or triple bond is a region of concentrated electrons that other molecules can attack, so alkenes and alkynes undergo addition reactions easily (Lesson 6). That is why ethene and propene are used to make plastics, antifreeze and many other products, while alkanes are used mostly as fuels.
Many natural molecules are alkenes too: the long chains in vegetable oils contain cis C=C bonds, and β-carotene, the orange pigment in carrots, has 11 C=C double bonds in a row.
Hands-on activityMake it, twist it, test it
You need: gumdrops or modelling clay in two colours, toothpicks, and 4 short pieces of pipe cleaner. Grown-up note: toothpicks are sharp.
- Build but-2-ene with a pipe-cleaner double bond (two bendy pieces) between C2 and C3. Put the two CH₃ ends on the same side (cis).
- Build a second model with them on opposite sides (trans).
- Try to turn the cis model into the trans model without pulling out any bond. Can you?
- Now replace the double bond with a single toothpick in both models (butane). Can you twist one into the other now?
- Build but-1-ene and check: does it have a cis/trans partner?
What to look for: with the double bond, the models cannot be twisted into each other, so cis and trans are different molecules. With a single bond they twist freely, so butane has no cis/trans isomers. But-1-ene has two H on C1, so swapping sides gives the same molecule.
Just for funRiddle: why did the alkyne break up with the alkane?
It wanted a relationship with a little more commitment: three bonds instead of one.
Your turn
1Write the molecular formula of hex-1-ene and of hex-1-yne.
Hexene: CₙH₂ₙ → C₆H₁₂. Hexyne: CₙH₂ₙ₋₂ → C₆H₁₀.
5 C; number from the right end so the C=C starts at C1: pent-1-ene (1-pentene).
4 C, triple bond at C2 from either end: but-2-yne (2-butyne).
4Draw the condensed formula of 3-methylpent-1-ene.
CH₂=CHCH(CH₃)CH₂CH₃ (C₆H₁₂).
Number from the end nearer the C=C: the right end. Then C1 = CH₃, C2 = C(CH₃), double bond C2=C3, C4 = CH₃. 2-methylbut-2-ene (2-methyl-2-butene).
6Does hex-3-ene have cis and trans isomers?
CH₃CH₂CH=CHCH₂CH₃: each C of the double bond has H and CH₂CH₃ → yes.
7Name the ring compound C₅H₈ that has one double bond in a five-membered ring.
More practice: warm-up
1What ending is used for a hydrocarbon with a triple bond?
2What is the general formula of an alkene with one double bond?
3Give the common name of ethyne.
4Which bond cannot rotate freely: C–C or C=C?
The two groups are on the same side of the double bond.
More practice: on your own
5 C with double bonds starting at C1 and C3 (from the left; from the right they start at C2 and C4). penta-1,3-diene (1,3-pentadiene).
2Name CH₃CH(CH₃)C≡CCH₂CH₃.
6-carbon chain with the triple bond. From the left: C≡C starts at C3, methyl at C2. From the right: C≡C starts at C3, methyl at C5. Tie on the triple bond, so give the branch the lowest number: 2-methylhex-3-yne.
3Draw (condensed) trans-pent-2-ene and explain why it is trans.
CH₃CH=CHCH₂CH₃ with the CH₃ (on C2) and the CH₂CH₃ (on C3) on opposite sides of the double bond. The two chain carbons attached to the C=C point to opposite sides of the line through the double bond.
4A student names a compound 3-methylbut-3-ene. Correct the name.
As written, the chain is C1–C2–C3(CH₃)=C4: CH₃CH₂C(CH₃)=CH₂. Number from the other end so the double bond starts at C1; the methyl is then on C2: 2-methylbut-1-ene.
5Which of these have cis/trans isomers: (a) CH₂=CHCl, (b) CH₃CH=CHCl, (c) (CH₃)₂C=CHCH₃?
(a) no (C1 has two H). (b) yes (C1: H and CH₃; C2: H and Cl). (c) no (C2 has two CH₃).
Challenge
1A hydrocarbon has the formula C₅H₈. List three different structural types it could be, with one example name each.
C₅H₈ is CₙH₂ₙ₋₂, two units of unsaturation: an alkyne (pent-1-yne), a diene (penta-1,3-diene) or a cycloalkene (cyclopentene). (Other examples are possible.)
2Name and draw (in words) the cis and trans isomers of ClCH=CHCl. Which one is polar, and which would you expect to have the higher boiling point?
cis-1,2-dichloroethene (both Cl on the same side) and trans-1,2-dichloroethene (Cl on opposite sides). Each C–Cl bond is polar. In the trans isomer the two bond dipoles point in opposite directions and cancel, so the molecule is non-polar. In the cis isomer they add, so it is polar. The cis isomer has dipole-dipole forces as well as London forces, so it has the higher boiling point (about 60 °C, compared with about 48 °C for trans).
3Explain why cyclohexene cannot have a "trans" double bond in its ring, even though the ring carbons have two different groups.
In a six-membered ring, the two chain carbons attached to the C=C are joined to each other through the ring, so they must be on the same side of the double bond. A trans arrangement would require the ring to stretch across the double bond, which is impossible with only four more carbons. (Trans double bonds are possible only in much larger rings, about eight carbons or more.)
Check your understandingQuiz
1. What is the IUPAC name of CH₂=CHCH₂CH₃?
2. Which formula could be an alkyne?
3. Which compound has cis and trans isomers?
4. How do you number the parent chain of an alkene?
5. What is the name of CH₃CH(CH₃)CH=CH₂?
6. Why are cis- and trans-but-2-ene different compounds?
For parents and teachersBig ideas (B2.2, B2.1, B3.5): alkenes and alkynes are named like alkanes, but the multiple bond controls the numbering and the ending. The rigid double bond creates cis-trans stereoisomers.
How to help: Ask your teen to explain why but-2-ene has cis and trans forms but but-1-ene does not. Ask them to show you on a model.
Common difficulties:
- Numbering from the branch end instead of the double-bond end.
- Forgetting the locant of the multiple bond ("butene" is ambiguous).
- Two styles of name: but-2-ene (current IUPAC) and 2-butene (older). Both are correct; be consistent.
- Claiming cis/trans isomers where one carbon has two identical groups.
This course chooses the parent chain as the longest chain containing the multiple bond, as Ontario textbooks do. (The newest IUPAC rules choose chains slightly differently in rare cases; students may meet this in university.)