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C. Metabolic Processes · Metabolic Processes

Totalling the ATP: Yield, Efficiency, Other Fuels and Control

C3.1 C3.3 C1.2 C2.1 A1.13About 70 minutes
Learning goals
  • I can total the ATP made from one glucose by aerobic respiration and explain why estimates range from about 30 to 38.
  • I can calculate the efficiency of aerobic respiration and relate it to the second law of thermodynamics.
  • I can explain how fats and proteins enter cellular respiration, and why fats yield more energy per gram.
  • I can explain how feedback inhibition of phosphofructokinase matches respiration to the cell's energy needs.

Words to know

ATP yield
The number of ATP molecules made per molecule of fuel (e.g. about 30 to 32 per glucose by aerobic respiration).
efficiency
The percentage of the fuel's free energy captured in a useful form: (energy in ATP ÷ energy released by the fuel) × 100%.
shuttle system
A set of reactions that carries the electrons of cytosolic NADH across the inner mitochondrial membrane, delivering them to NAD⁺ or FAD inside.
β-oxidation (beta-oxidation)
The pathway in the mitochondrial matrix that cuts fatty acids into two-carbon acetyl-CoA units, making NADH and FADH₂.
deamination
Removal of the amino group (as ammonia) from an amino acid so its carbon skeleton can enter respiration; liver cells turn the ammonia into urea.
feedback inhibition
Control of a pathway in which a product (such as ATP or citrate) inhibits an enzyme near the start of the pathway.
allosteric regulation
Control of an enzyme by a molecule that binds at a site other than the active site (an allosteric site), changing the enzyme's shape and activity.

How good a deal is respiration?

A gasoline car engine converts only about a quarter to a third of the fuel's energy into motion; the rest is heat out the tailpipe and radiator. How does your body compare? In this lesson you will add up all the ATP from one glucose, calculate the efficiency of respiration, and see how the cell also burns fats and proteins and adjusts its rate to its needs.

Remember from Lessons 4 to 6

From Lessons 4 to 6, per glucose: glycolysis gives 2 ATP and 2 NADH; pyruvate oxidation gives 2 NADH; the Krebs cycle gives 2 ATP, 6 NADH and 2 FADH₂. Each NADH gives about 2.5 ATP and each FADH₂ about 1.5 ATP by oxidative phosphorylation.

Adding up the ATP

There is one complication. The 2 NADH made by glycolysis are in the cytosol, and the inner mitochondrial membrane doesn't let NADH through. Instead, shuttle systems pass their electrons in:

  • In liver, kidney and heart cells, a shuttle passes the electrons to NAD⁺ inside the matrix, so each cytosolic NADH is worth about 2.5 ATP.
  • In skeletal muscle and brain cells, a different shuttle passes them to FAD, so each is worth only about 1.5 ATP.

Putting it all together (modern estimate):

SourceSubstrate-level ATPCarriersATP from carriersTotal
Glycolysis22 NADH (cytosol)3 to 55 to 7
Pyruvate oxidation02 NADH55
Krebs cycle26 NADH + 2 FADH₂15 + 3 = 1820
Total per glucose426 to 2830 to 32
ATP yield per glucose using about 2.5 ATP per NADH and 1.5 per FADH₂.
ATP per glucose (modern estimate, about 30 to 32)223–55153glycolysis 2Krebs 2glycolysis NADH (3–5, via shuttle)pyruvate ox. NADH 5Krebs NADH 15FADH₂ 3substrate-level: 4 ATP; oxidative phosphorylation: 26–28 ATP
Where the ATP comes from. Only 4 ATP per glucose are made by substrate-level phosphorylation; the other 26 to 28 come from oxidative phosphorylation, mostly from the NADH of the Krebs cycle.

Why some textbooks say 36 or 38

Older textbooks (and some still used in Ontario) assumed 3 ATP per NADH and 2 ATP per FADH₂, which gives 36 ATP (with the muscle shuttle) or 38 ATP (with the liver shuttle, or in prokaryotes, which have no mitochondrial membrane to cross). Later measurements showed that the H⁺ gradient is also used to move ADP, Pᵢ and ATP across the membrane, and some H⁺ leaks back, so the real yield is lower: about 30 to 32. The ATP number is a theoretical maximum that depends on conditions; it is not a fixed count like the number of CO₂.

Use whichever values your teacher or exam asks for, and always state your assumption (for example, "assuming 2.5 ATP per NADH").

How efficient is it?

Efficiency = (energy captured in ATP ÷ energy released by glucose) × 100%

With 32 ATP × 30.5 kJ/mol = 976 kJ, and 2870 kJ released per mole of glucose:

efficiency = 976 ÷ 2870 × 100% ≈ 34%.

That compares well with a car engine. The other 66% or so is released as heat, exactly as the second law predicts. In birds and mammals, that heat isn't wasted: it maintains body temperature.

Other fuels: fats and proteins

Your cells don't run only on glucose. Fats and proteins enter the same pathways at different points.

  • Fats (triglycerides) are split into glycerol and fatty acids. Glycerol is converted to G3P and enters glycolysis. Fatty acids are cut into two-carbon pieces by β-oxidation in the matrix; each cut makes 1 NADH, 1 FADH₂ and 1 acetyl-CoA, which enters the Krebs cycle.
  • Proteins are digested into amino acids. Usually amino acids are used to build proteins, but when they are used as fuel, the amino group is removed (deamination). The ammonia is toxic, so the liver converts it to urea, which the kidneys excrete (you will study this in the Homeostasis unit). The remaining carbon skeleton enters as pyruvate, acetyl-CoA or a Krebs intermediate.

Why fat is so energy-dense: fatty acids are long chains of carbon with many C–H bonds: they are highly reduced (Lesson 3), so they provide many electrons to the ETC. Fat provides about 37 kJ/g, compared with about 17 kJ/g for carbohydrates or proteins. (Nutrition labels in Canada list energy in Calories: 1 Calorie = 1 kcal = 4.184 kJ.)

carbohydratesfats (triglycerides)proteinsglucose and other sugarsglycerolfatty acidsamino acidsglycolysispyruvateacetyl-CoAKrebs cycle → ETC→ G3Pβ-oxidationdeamination:NH₃ → urea
Carbohydrates, fats and proteins all feed into respiration. Glycerol enters glycolysis as G3P; fatty acids become acetyl-CoA by β-oxidation; amino acids lose their amino group and enter at several points (dashed arrows).

Matching supply to demand: control at PFK

A cell shouldn't burn fuel faster than it needs ATP. The main control point is the enzyme phosphofructokinase (PFK), step 3 of glycolysis, which commits the sugar to being split. PFK is an allosteric enzyme (from the Biochemistry unit):

  • High ATP (plenty of energy) binds an allosteric site and inhibits PFK.
  • High citrate (the Krebs cycle is backed up) also inhibits PFK.
  • High AMP and ADP (energy is being used up) activate PFK.

This is feedback inhibition: products made later (ATP, citrate) slow down an early step. When you start running, ATP is used, ADP and AMP rise, PFK speeds up, and respiration accelerates within seconds.

phosphofructokinase(glycolysis step 3)ATP (high)citrate (high)AMP, ADP (high)− inhibits− inhibits+ activatesBoth act at allosteric sites,not at the active site.lots of energy →slow down;low energy →speed up
Feedback control of respiration. ATP and citrate inhibit phosphofructokinase; AMP and ADP activate it. Respiration speeds up when energy is being used and slows when ATP is plentiful.
Worked example

Let's compare the efficiency of two assumptions

Calculate the efficiency of aerobic respiration assuming (a) 30 ATP per glucose and (b) 38 ATP per glucose. Use 30.5 kJ/mol per ATP and 2870 kJ/mol for glucose.

  1. (a) 30 × 30.5 = 915 kJ; 915 ÷ 2870 × 100% = 31.9%.
  2. (b) 38 × 30.5 = 1159 kJ; 1159 ÷ 2870 × 100% = 40.4%.
  3. Either way, most of the energy (about 60 to 68%) is released as heat.

Efficiency is about 32% (30 ATP) to 40% (38 ATP). State your assumption when you report it.

Worked example

Let's find the ATP yield of a fatty acid

Palmitic acid has 16 carbons. β-oxidation cuts it into acetyl-CoA units. Each cut produces 1 NADH and 1 FADH₂. Activating the fatty acid costs the equivalent of 2 ATP. Each acetyl-CoA yields 10 ATP through the Krebs cycle and ETC (3 NADH × 2.5 + 1 FADH₂ × 1.5 + 1 ATP). Calculate the ATP yield of palmitic acid.

  1. Number of acetyl-CoA: 16 ÷ 2 = 8.
  2. Number of cuts: 8 pieces need 7 cuts → 7 NADH and 7 FADH₂.
  3. ATP from β-oxidation: 7 × 2.5 + 7 × 1.5 = 17.5 + 10.5 = 28.
  4. ATP from acetyl-CoA: 8 × 10 = 80.
  5. Total: 28 + 80 − 2 = 106 ATP.

One palmitic acid yields about 106 ATP, compared with 32 for glucose. Per carbon, that's 6.6 ATP vs 5.3 ATP: fat is the more reduced, more energy-rich fuel.

Just for fun

Phosphofructokinase may have the longest name in this lesson, but its job description is short: when ATP piles up, it puts up a sign that says "Closed. Come back when you're tired."

Hands-on activity

Read the labels: fuel in your kitchen

You need: 4 or 5 food packages with Nutrition Facts tables (for example, a granola bar, crackers, peanut butter, milk and cheese), a calculator, a notebook.

  1. For each food, record the serving size (g), Calories, and grams of fat, carbohydrate and protein.
  2. Convert to kilojoules: kJ = Calories × 4.184.
  3. Estimate the energy from each nutrient: fat × 37 kJ/g, carbohydrate × 17 kJ/g, protein × 17 kJ/g. Add them and compare with the label's total. (Fibre and rounding cause small differences.)
  4. Calculate the percentage of each food's energy that comes from fat.
  5. Make a bar graph of percentage energy from fat, carbohydrate and protein for each food.

Questions:

  • Which food has the highest energy per gram? Use the idea of reduced molecules to explain why.
  • Which nutrients will enter respiration as acetyl-CoA? Which as G3P or pyruvate?
  • Why does the label total not match your estimate exactly?

What to look for: high-fat foods (peanut butter, cheese) have the highest energy per gram, because fats are highly reduced (many C–H bonds). Fatty acids enter as acetyl-CoA; glycerol as G3P; sugars through glycolysis; amino acids at several points after deamination. Differences come from rounding on the label, fibre (which provides less energy) and the 17/37 kJ/g values being averages.

Your turn

1

Using 2.5 ATP per NADH and 1.5 per FADH₂, calculate the ATP from oxidative phosphorylation for the 2 NADH from pyruvate oxidation and the 6 NADH and 2 FADH₂ from the Krebs cycle.

2

Why do cytosolic NADH from glycolysis sometimes yield fewer ATP than mitochondrial NADH?

3

Calculate the efficiency of respiration if 32 ATP are made per glucose.

4

Where does the rest of the energy from glucose go?

5

How does glycerol from fat enter respiration? How do fatty acids enter?

6

What happens to the amino group when an amino acid is used as fuel?

7

Name two molecules that inhibit phosphofructokinase, and one that activates it.

More practice: warm-up

1

What is the modern estimate for ATP per glucose in aerobic respiration?

2

How many ATP per glucose are made by substrate-level phosphorylation?

3

About how many kJ per gram does fat provide?

4

What is the name of the pathway that breaks fatty acids into acetyl-CoA?

5

Is PFK regulation an example of positive or negative feedback?

More practice: on your own

1

Show how the old figure of 36 ATP per glucose is calculated (assume 3 ATP per NADH, 2 per FADH₂, and the shuttle that delivers glycolytic electrons to FAD).

2

A 30 g serving of almonds has 15 g fat, 6 g carbohydrate and 6 g protein. Estimate its energy in kJ and in Calories.

3

Explain why fat yields more energy per gram than glucose, using redox ideas.

4

Explain why PFK, rather than an enzyme near the end of glycolysis, is the main control point.

5

A person's cells contain high citrate and high ATP levels. Predict the rate of glycolysis and explain.

Challenge

1

A prokaryote has no mitochondria. Explain why it can theoretically make 38 ATP per glucose with the older assumptions (3 per NADH, 2 per FADH₂), and where its ETC is located.

2

Calculate the ATP yield of a 12-carbon fatty acid (lauric acid) using the same method as the worked example.

3

During a long cross-country ski race, an athlete's muscle cells use more fat as fuel. Explain why fat provides more ATP per gram, but carbohydrate provides more ATP per litre of oxygen consumed.

Check your understanding

Quiz

1.

Using modern estimates, about how many ATP are made from one glucose in aerobic respiration?

2.

If 32 ATP (30.5 kJ/mol each) are made from 1 mol of glucose (2870 kJ/mol), the efficiency is about:

3.

How do fatty acids enter cellular respiration?

4.

Why does fat release more energy per gram than carbohydrate?

5.

Which change would activate phosphofructokinase?

6.

The NADH made in glycolysis yields only about 1.5 ATP each in skeletal muscle because:

For parents and teachers

Big idea: The ATP yield of respiration (about 30 to 32 per glucose, efficiency about a third) reflects the second law; other fuels enter the same pathways, and respiration is regulated by feedback at PFK (C3.1, C3.3). The nutrition-label activity links the chemistry to everyday choices (C1.2).

How to help: Check that your teen states assumptions ("using 2.5 ATP per NADH") when calculating yields, since textbooks differ. The label activity is a natural kitchen-table conversation; keep it about chemistry and energy, not about judging foods or bodies.

Common difficulties:

  • Believing there is one "correct" ATP number. It is an estimate that depends on assumptions.
  • Forgetting the 2 ATP spent to activate a fatty acid, or miscounting the number of β-oxidation cuts (one fewer than the number of acetyl-CoA).
  • Thinking ATP activates PFK. High ATP inhibits it.