Roads that never meet
On a highway overpass, one road passes over another. The roads point in different directions, so they are not parallel, but they never meet either: one is always above the other. In two-space that is impossible: two non-parallel lines in a plane must cross. In three-space it is common, and such lines are called skew lines.
In this lesson you will sort any two lines in three-space into one of four cases, and find the point of intersection when there is one.
Four possible configurations
For two lines L₁: r = r₁ + tm₁ and L₂: r = r₂ + sm₂ in three-space:
Parallel directions (m₂ = km₁):
- Coincident: a point of one line is on the other. Every point is shared.
- Parallel and distinct: no point is shared.
Non-parallel directions:
- Intersecting: they meet in exactly one point. The two lines lie in one plane.
- Skew: they never meet. No plane contains both lines.
How to test. Use a different parameter for each line (t and s), and set the coordinates equal:
r₁ + tm₁ = r₂ + sm₂ gives three equations in only two unknowns.
Solve two of them for t and s, then substitute into the third. If it checks, the lines intersect; substitute t into L₁ to find the point. If it fails, the lines are skew.
Worked exampleExample 1: Two lines that intersect
Find the intersection of L₁: r = [1, 2, 3] + t[1, −1, 2] and L₂: r = [4, 0, 6] + s[2, −1, 1].
- The directions [1, −1, 2] and [2, −1, 1] are not multiples, so the lines intersect or are skew.
- Set coordinates equal: 1 + t = 4 + 2s, 2 − t = −s, 3 + 2t = 6 + s.
- From the second equation, s = t − 2. Substitute into the first: 1 + t = 4 + 2t − 4, so t = 1 and s = −1.
- Check the third: 3 + 2(1) = 5 and 6 + (−1) = 5 ✓.
- Point: t = 1 in L₁ gives (2, 1, 5). (Check in L₂ with s = −1: (4 − 2, 0 + 1, 6 − 1) = (2, 1, 5) ✓.)
The lines intersect at (2, 1, 5).
Worked exampleExample 2: Skew lines
Classify L₁: r = [1, −1, 2] + t[2, 1, 0] and L₂: r = [0, 3, 1] + s[1, −1, 1].
- Directions [2, 1, 0] and [1, −1, 1] are not parallel.
- Equations: 1 + 2t = s, −1 + t = 3 − s, 2 = 1 + s.
- The third gives s = 1. Then the first gives t = 0.
- Check the second: −1 + 0 = −1, but 3 − 1 = 2. −1 ≠ 2.
No values of t and s work: the lines are skew.
Worked exampleExample 3: Parallel lines
Classify L₁: r = [2, 0, 1] + t[1, −2, 3] and L₂: r = [0, 1, 1] + s[−2, 4, −6].
- [−2, 4, −6] = −2[1, −2, 3], so the directions are parallel.
- Is (0, 1, 1) on L₁? From x: 2 + t = 0, so t = −2. Then y = 0 − 2(−2) = 4, but the point has y = 1.
Check your understandingQuiz
1. Skew lines are lines in three-space that:
2. Two lines have direction vectors [2, −1, 4] and [−4, 2, −8]. The lines must be:
3. The x-axis and the line x = 0, z = 1 (parallel to the y-axis through (0, 0, 1)) are:
4. For two non-parallel lines, you solve two of the equations and get t = 1 and s = 1, but the third equation fails. The lines are:
5. Where do r = [1, 2, 3] + t[1, −1, 2] and r = [4, 0, 6] + s[2, −1, 1] intersect?
6. Which configuration of two lines can happen in three-space but never in two-space?